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## Homework Statement

A ball is thrown 2.8m/s vertically upward from a window that is 3.6m above the ground. calculate the amount of time the ball spends in the air.

## Homework Equations

quadratic equation

d = Vi(t) + 1/2(a)(t)

^{2}

## The Attempt at a Solution

d = Vi(t) + 1/2(a)(t)

^{2}

3.6m =2.8 m/s[up](t) + 1/2(-9.8m/s

^{2}[up])(t)^2

0 = -4.9m/s

^{2}[up](t)

^{2}+ 2.8m/s[up](t) - 3.6m

__________________

into the quadratic formula:

t = [-(2.8) +- sqrt(2.8

^{2}- 4(-4.9)(-3.6))] / 2(-4.9)

i end up with a negative under the root sign?