Calculating Distance of Two Speakers Producing 162Hz Sound

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The discussion focuses on calculating the distance between two speakers producing a 162Hz sound in phase, with an intensity minimum located 3.75m from the nearer speaker. The correct formula to use is the difference in distance divided by the wavelength equals the phase difference divided by 2π. The wavelength for a 162Hz sound, given the speed of sound at 345m/s, is approximately 2.13m. The final calculation shows that the distance to the further speaker is 4.09m, but the phase difference should be considered as nπ for intensity minima.

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Two speakers produce a 162Hz sound in phase. If an intensity minimum is located 3.75m from the nearer speaker, find the distance to the further speaker if the speed of sound in the air is 345m/s.

Would it go like this
d(1)-d(2)/wavelength=phase difference/2pi
x-3.75/2.13=1/2pi
x=4.09m

This doesn't seem quite right let me know what to do please.
 
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lilkrazyrae said:
Two speakers produce a 162Hz sound in phase. If an intensity minimum is located 3.75m from the nearer speaker, find the distance to the further speaker if the speed of sound in the air is 345m/s.
Would it go like this
d(1)-d(2)/wavelength=phase difference/2pi
x-3.75/2.13=1/2pi
x=4.09m
This doesn't seem quite right let me know what to do please.
The difference in distance must equal a multiple of half a wavelength for a minimum (phase difference = [itex]n\pi[/itex] not [itex]2n\pi[/itex]).

AM
 

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