Calculating Distance Traveled: Car Speed and Cliff Jump Duration

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SUMMARY

The discussion centers on calculating the horizontal distance a car travels after driving off a cliff at a speed of 50 km/h for 10 seconds. The user correctly identifies that there is zero acceleration in the horizontal direction, leading to the conclusion that the horizontal distance can be calculated using the formula d = vt, where v is the initial velocity and t is the time in the air. The final calculation shows that the car would land 138.89 meters from the base of the cliff.

PREREQUISITES
  • Understanding of basic physics concepts such as velocity and acceleration
  • Familiarity with kinematic equations, specifically d = vt
  • Knowledge of horizontal motion principles in projectile motion
  • Ability to perform unit conversions, particularly between km/h and m/s
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  • Explore real-world applications of kinematic equations in physics
  • Investigate the effects of air resistance on projectile motion
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Students studying physics, educators teaching kinematics, and anyone interested in understanding the principles of projectile motion and distance calculations.

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Homework Statement



if a car drove off a cliff at 50km/h, how far wouuld it land from the base of the cliff if it was in the air for 10s

Homework Equations



not sure

The Attempt at a Solution


i used v=at
i rearrachnged that 2 v/t=a
then i choosed to use d=1/2xaxt^2
 
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There is zero acceleration in the horizontal direction. (The horizontal component of velocity doesn't change.)
 

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