A car is parked near a cliff overlooking the
ocean on an incline that makes an angle of
14 with the horizontal. The negligent driver
leaves the car in neutral, and the emergency
brakes are defective. The car rolls from rest
down the incline and has a velocity 5 m/s
when it reaches the edge of the cliff. The cliff
is 34.6 m above the ocean. How far is the car from the base of the cliff
when the car hits the ocean? The acceleration
of gravity is 9.8 m/s2 .
Answer in units of m
d = (Vi)t + .5at^2
[d][horizontal] = (Vi * √(2 height)) / [a][gravity]
The Attempt at a Solution
I would like to be able to plug into the second equation, but I'm not sure if the angle of the cliff would not allow me to do this. I am kind of unsure if these are even the right equations to be using.