Calculating Drag Through A Pipe

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Concrete is pumped through a pipe, with the flow velocity at 0.2 m/s for the concrete more than 10 cm from the wall, while the wall itself remains stationary. The viscosity of the concrete is given as 5 Pa s, and the shear stress can be calculated using the formula: shear stress = viscosity x (velocity gradient). The velocity gradient is determined to be 2 s^-1, leading to a shear stress of 10 N/m². The discussion clarifies that the area of the pipe is not needed for the final answer, as the shear stress already represents the drag force per unit area.
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MODERATOR NOTE: NO TEMPLATE - MISPLACED HOMEWORK
Hi All
I was hoping someone could help with the following problem:-

Concrete is being pumped along a pipe. All of the concrete that is more then 10cm from the wall of the pipe is moving at 0.2m/s, and the material in contact with the pipe wall is not moving. Assuming that the concrete has a viscosity of 5 Pa s, calculate the drag on each square meter of the surface of the pipe.

I know that the Viscosity = Shear Stress / Shear Strain
and Shear Stress = Force / Area
and Shear Strain = Change in Length / Original Length

But that it is.

The answer is meant to be:-
Shear stress = Viscosity x ((V1 – V2) / dy)
Shear stress = 5 x (0.2 / 0.1)
Shear stress = 10 N/m2

I assume the pipe diameter to be 20cm giving me an Area of 0.03146m^2

I'm not sure where to take it from here.

Any ideas?

Thank you.
 
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tomtomtom1 said:
MODERATOR NOTE: NO TEMPLATE - MISPLACED HOMEWORK
Hi All
I was hoping someone could help with the following problem:-

Concrete is being pumped along a pipe. All of the concrete that is more then 10cm from the wall of the pipe is moving at 0.2m/s, and the material in contact with the pipe wall is not moving. Assuming that the concrete has a viscosity of 5 Pa s, calculate the drag on each square meter of the surface of the pipe.

I know that the Viscosity = Shear Stress / Shear Strain
and Shear Stress = Force / Area
and Shear Strain = Change in Length / Original Length
This is not correct. Viscosity = Shear Stress / Shear Rate (i.e., velocity gradient)
But that it is.

The answer is meant to be:-
Shear stress = Viscosity x ((V1 – V2) / dy)
Shear stress = 5 x (0.2 / 0.1)
Shear stress = 10 N/m2
The velocity gradient is ##\Delta V/\Delta y##, which is 0.2/0.1 = ##2 s^{-1}##
So the shear stress is the same as the drag force per unit area = 10 N/m^2 = 10 Pa
I assume the pipe diameter to be 20cm giving me an Area of 0.03146m^2

I'm not sure where to take it from here.
You don't need the pipe surface area. You already have your answer.
 
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