# Calculating Electric Field at (2.00,0)

• -EquinoX-
In summary, the conversation discusses finding the electric field at a specific position (2.00, 0) with multiple charges present. It mentions using superposition to calculate the total electric field and clarifies the distances involved. It also addresses the possibility of a different position (0, 2.00) and the use of Pythagorean theorem to find the distances in that case.
-EquinoX-

## Homework Statement

Find the electric field at position (2.00, 0)

## The Attempt at a Solution

I am just confused by the question actually, does it mean at point 2 m to the right of 0,0? or is it to the left?

The way I would solve this problem is by finding the electric field that each charges made 2 m from the point, for example the -.4nC, we can find the electric field at 2.00 by ke * -.4nC/2.5^2, and as well for the others and sum them all together, am I right?

-EquinoX- said:
I am just confused by the question actually, does it mean at point 2 m to the right of 0,0?

Yes. The way I read the diagram, the 5nC is at the origin and they are asking for the point 1.2 m to the right of the 3nC charge.

The way I would solve this problem is by finding the electric field that each charges made 2 m from the point, for example the -.4nC, we can find the electric field at 2.00 by ke * -.4nC/2.5^2, and as well for the others and sum them all together, am I right?

Yes. Superposition is right. The distances for each (left to right) to be clear would be 2.5, 2, 1.2 .

so basically it's just ke * -.4nC/2.5^2 + ke * 5nC/2^2 + ke * 3nC/1.2^2

That's what it looks like to me.

What if the question now is (0, 2.00) instead of (2.00,0)?

-EquinoX- said:
What if the question now is (0, 2.00) instead of (2.00,0)?

That would mean apparently it was on the y axis. In which case get out your Pythagoras.

I use the pythagorean theory to find the distance from the -4 and 3 charhea to the point (0, 2.00) only right?

## What is the formula for calculating electric field at a specific point?

The formula for calculating electric field at a specific point is E = kq/r^2, where E is the electric field, k is Coulomb's constant (9 x 10^9 N*m^2/C^2), q is the magnitude of the point charge, and r is the distance between the point charge and the point where the electric field is being calculated.

## How do I determine the direction of the electric field at a specific point?

The direction of the electric field at a specific point is determined by the direction of the force that a positive test charge would experience if placed at that point. The direction of the electric field is always directed away from positive charges and towards negative charges.

## How does the distance from the point charge affect the electric field at (2.00,0)?

The electric field at a specific point is inversely proportional to the square of the distance from the point charge. This means that as the distance increases, the electric field decreases. In this case, at a distance of (2.00,0), the electric field will be less than at a distance of (1.00,0).

## Can I use the formula for calculating electric field at (2.00,0) for multiple point charges?

Yes, the formula E = kq/r^2 can be used for multiple point charges by calculating the electric field for each individual charge and then vectorially adding them to find the net electric field at (2.00,0).

## Are there any units for electric field at (2.00,0)?

Yes, the units for electric field are newtons per coulomb (N/C) or volts per meter (V/m).

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