Calculating Electric Field from a Long Straight Wire

Click For Summary
SUMMARY

The discussion focuses on calculating the electric field generated by a long straight wire with a linear charge density of 1.49×10-10 C/m. The formula used is E = (λ)/(2πε0r), where E is the electric field, λ is the charge per unit length, ε0 is the permittivity of free space (8.85×10-12 C2/(N·m2)), and r is the distance from the wire. The goal is to find the distance r when E equals 2.49 N/C. The confusion regarding the term "lambda" is clarified as referring to linear charge density rather than wavelength.

PREREQUISITES
  • Understanding of electric fields and Coulomb's law
  • Familiarity with linear charge density concepts
  • Basic knowledge of the permittivity of free space
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Learn how to derive electric field equations for different charge distributions
  • Study the concept of linear charge density in electrostatics
  • Explore the implications of permittivity in electric field calculations
  • Practice solving problems involving electric fields from charged wires
USEFUL FOR

Physics students, electrical engineers, and anyone interested in understanding electrostatics and electric field calculations related to charged conductors.

Soaring Crane
Messages
461
Reaction score
0
A very long straight wire has charge per unit length 1.49×10-10 C/m.


At what distance from the wire is the magnitude of the electric field equal to 2.49 N/C?



Use 8.85×10-12 C^2/(N*m^2) for the permittivity of free space and use pi = 3.1416 for E = (lambda)/(2*pi*permittivity of free space*r).

Given:
E = 2.49 N/C

I have no idea what to do with this formula. Why is wavelength needed and what is the variable we are trying to find? I am lost.

Thanks.
 
Physics news on Phys.org
Soaring Crane said:
Why is wavelength needed and what is the variable we are trying to find? I am lost.
In this formula, lambda stands for the "charge per unit length", not wavelength. You are trying to find the distance from the wire, which is "r".
 
\lambda is not a wavelength,it's the linear charge density and it's measured in C/m.
Plug in all the numbers in the formula & see what happens...

Daniel.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
969
Replies
14
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 16 ·
Replies
16
Views
1K
Replies
14
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
8
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K