Calculating Electric Field Intensity with Two Spherical Shells

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SUMMARY

The discussion focuses on calculating electric field intensity generated by two spherical shells, where the inner shell has a radius 'a' and a total charge of -Q, while the outer shell has a radius 'b' and a total charge of +Q. The electric field intensity is defined as zero for regions outside the shells and varies within them based on the presence of a point charge. Specifically, for the region between the shells (a ≤ R ≤ b), the electric field intensity is given by E = -Q/(4πε₀R³) R when no point charge is present, and E = Q/(4πε₀R³) R when a point charge is located at the center. The net effect of the outer shell is zero when considering the inner shell's influence.

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john88
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Hi

Two spherical shells where the inner has a radius a and the outer a radius of b. The inner has a total charge of -Q whereas the outer shell has a total charge +Q. The question is to calculate the electric field intensity everywhere in space.
My question is now, how do I choose the limits for example [tex]a \leq R \leq b[/tex] I have two examples below

No point charge in the middle

[tex]E = 0, 0 \leq R \prec a[/tex] (not equal to a)

[tex]E = -\frac{Q}{4\pi\epsilon_{o}R^3} \bold{R}[/tex] [tex]a \leq R \leq b[/tex]

[tex]E = 0, b \prec R \prec \infty[/tex]

A point charge in the middle

[tex]E = \frac{Q}{4\pi\epsilon_{o}R^3} \bold{R}[/tex] [tex]0 \prec R \leq a[/tex] why set equal to a here and not when there aint no point charge in the middle?

[tex]E = 0[/tex] [tex]a \prec R \prec b[/tex]

[tex]E = \frac{Q}{4\pi\epsilon_{o}R^3} \bold{R}[/tex] [tex]b \leq R \prec \infty[/tex]
 
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A point within a spherical shell experiences 0N/C. For R between a and b, inner shell is effective and outer shell's net effect is 0N/C...this works for even insulators so long as charge is evenly distributed across the shell (question didn't specify whether it was a conductor or something else). If the thickness of the shells is negligible, then you could consider the effect of the inner shell as that due to a point charge.
 
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