Calculating Electric Field Intensity with Two Spherical Shells

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 2K views
john88
Messages
16
Reaction score
0
Hi

Two spherical shells where the inner has a radius a and the outer a radius of b. The inner has a total charge of -Q whereas the outer shell has a total charge +Q. The question is to calculate the electric field intensity everywhere in space.
My question is now, how do I choose the limits for example [tex]a \leq R \leq b[/tex] I have two examples below

No point charge in the middle

[tex]E = 0, 0 \leq R \prec a[/tex] (not equal to a)

[tex]E = -\frac{Q}{4\pi\epsilon_{o}R^3} \bold{R}[/tex] [tex]a \leq R \leq b[/tex]

[tex]E = 0, b \prec R \prec \infty[/tex]

A point charge in the middle

[tex]E = \frac{Q}{4\pi\epsilon_{o}R^3} \bold{R}[/tex] [tex]0 \prec R \leq a[/tex] why set equal to a here and not when there aint no point charge in the middle?

[tex]E = 0[/tex] [tex]a \prec R \prec b[/tex]

[tex]E = \frac{Q}{4\pi\epsilon_{o}R^3} \bold{R}[/tex] [tex]b \leq R \prec \infty[/tex]
 
Physics news on Phys.org
A point within a spherical shell experiences 0N/C. For R between a and b, inner shell is effective and outer shell's net effect is 0N/C...this works for even insulators so long as charge is evenly distributed across the shell (question didn't specify whether it was a conductor or something else). If the thickness of the shells is negligible, then you could consider the effect of the inner shell as that due to a point charge.
 
Last edited: