Calculating Electric Field of Spherical Conductor

Click For Summary

Homework Help Overview

The discussion revolves around calculating the electric field of a spherical conductor with an inner cubic cavity containing a charge. The problem involves understanding the distribution of charge on the conductor's surface and how it affects the electric field at a point outside the sphere.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the application of Gauss's Law and the significance of the charge enclosed by a Gaussian surface. There are attempts to express the enclosed charge in terms of the variables defined in the problem. Questions arise regarding the relevance of the surface charge density and how it should be incorporated into the calculations.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been provided regarding the need to account for the surface charge density, indicating a productive direction in the conversation.

Contextual Notes

Participants are navigating the implications of the charge density on the surface of the sphere and its effect on the electric field calculation. There is uncertainty about the necessity of all given information for solving the problem.

jackxxny
Messages
39
Reaction score
0

Homework Statement


Let's say I have :
Spherical conductor of radius=x;
Spherical conductor has a inner cubic cavity of side = b;
inside the cubic cavity we have a charge = y;
the surface of the sphere has a charge density = z;
I need to calculate the electric field at some point g, where g>r;


Homework Equations



I believe we can say that the sphere is uniformly charged.

The Attempt at a Solution



I don't need all of these information right?

All I do is

E= y/4*pi*E0*g2

?
 
Physics news on Phys.org
HINT: This is a Gauss's Law problem. How much charge is enclosed by your Gaussian surface?
 
the charge enclose to the surface is just Q.
 
What do you mean by Q? Express the charge enclosed using the variables and quantities defined by the problem.
 
sorry i mean y.

so all i have to do for the outside electric field is:y/4*pi*eog2
 
That's all i have to do right?
 
What about the charge density on the surface of the sphere? You need to take that into account.
 
i think this may work:



Electric field at point g=


(1/4*pi*eo)*∫ p d(tao)

= (1/4*pi*eo)*∫chargedensity(z) *radius(x)^2 * sin(theta) d(x) d(theta) d (phi)

will that work?
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
5K
Replies
2
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
9
Views
2K
Replies
4
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 3 ·
Replies
3
Views
162
Replies
4
Views
3K