Calculating Electric Field of Spherical Conductor

[jackxxny]

Homework Statement

Let's say I have :
Spherical conductor of radius=x;
Spherical conductor has a inner cubic cavity of side = b;
inside the cubic cavity we have a charge = y;
the surface of the sphere has a charge density = z;
I need to calculate the electric field at some point g, where g>r;

Homework Equations

I believe we can say that the sphere is uniformly charged.

The Attempt at a Solution

I don't need all of these information right?

All I do is

E= y/4*pi*E₀*g²

?

 

[G01]

HINT: This is a Gauss's Law problem. How much charge is enclosed by your Gaussian surface?

 

[jackxxny]

the charge enclose to the surface is just Q.

 

[G01]

What do you mean by Q? Express the charge enclosed using the variables and quantities defined by the problem.

 

[jackxxny]

sorry i mean y.

so all i have to do for the outside electric field is:y/4*pi*e_og²

 

[jackxxny]

That's all i have to do right?

 

[G01]

What about the charge density on the surface of the sphere? You need to take that into account.

 

[jackxxny]

i think this may work:



Electric field at point g=


(1/4*pi*eo)*∫ p d(tao)

= (1/4*pi*eo)*∫chargedensity(z) *radius(x)^2 * sin(theta) d(x) d(theta) d (phi)

will that work?