Calculating Electric Force with Coulomb's Law: Glass and Rubber Ball Example

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SUMMARY

The electric force between a glass ball with a charge of +2.8 µC and a rubber ball with a charge of -4.8 µC, separated by a distance of 4.5 cm, can be calculated using Coulomb's Law. The formula F = k * Q1 * Q2 / r^2 applies, where k is the electrostatic constant (approximately 8.99 x 10^9 N m²/C²). The correct calculation yields an electric force of approximately -59.73 N, indicating an attractive force due to the opposite charges of the balls.

PREREQUISITES
  • Coulomb's Law
  • Understanding of electric charge units (microcoulombs)
  • Basic algebra for manipulating equations
  • Knowledge of the electrostatic constant (k)
NEXT STEPS
  • Review the derivation and applications of Coulomb's Law
  • Learn about the electrostatic constant and its significance in calculations
  • Explore examples of electric force calculations with varying charge values
  • Investigate the effects of distance on electric force using different charge configurations
USEFUL FOR

Students studying physics, particularly those focusing on electrostatics, as well as educators looking for practical examples of Coulomb's Law applications.

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Homework Statement




What is the electric force between a glass ball that has +2.8 µC of charge and a rubber ball that has -4.8 µC of charge when they are separated by a distance of 4.5 cm?


2. Homework Equations

F=k*Q1*Q2/r^2

3. The Attempt at a Solution
-59.6507
-8.8888888.889
4.4380e12
 
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i got -59.7333 but it is wrong HELP please
 

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