Calculating emf from angular velocity

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Homework Help Overview

The discussion revolves around calculating the electromotive force (emf) generated by a rotating metal propeller in a magnetic field, specifically using Faraday's law of electromagnetic induction. The problem involves understanding the relationship between angular velocity, area swept by the propeller, and the resulting emf.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the derivation of the emf equation and question the disappearance of the N value in the context of a single wire sweeping out an area. They also discuss the calculation of emf based on the propeller's length and angular velocity, with some confusion regarding the average speed of the propeller's tip.

Discussion Status

Participants are actively engaging with the problem, raising questions about the assumptions made in the calculations and exploring different interpretations of the equations involved. Some guidance has been offered regarding the varying speeds along the length of the propeller.

Contextual Notes

There is a noted discrepancy between the calculated emf values, with participants questioning the application of the formulas and the assumptions regarding speed and area. The problem is framed within the constraints of a homework assignment, which may limit the information available for discussion.

Masafi
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I had 2 questions:

1. My textbook derives that the equation from lenz's and faraday's law

emf = - d(N*flux)/dt
= B * dA/dT

where dA/dt = length * speed

However, why does the N value disappear in the new equation?


Also, this question is given after:

2. A metal propeller rotates in a verical plane with angular vel 85 rad per sec. The length of the propeller from tip to tip is 2.5m. Calculate emf generated between centre and tip of properller. The horizontal component of Earth's magnetic field is 22 x 10^(-6) T (micro Tesla)

The answer is 1.5 x 10^(-3) V. I don't get this.

I did emf = B * dA/dt

dA/dt = length * speed
= 1.25 * (1.25 * 85)

which gives emf = 2.9 x 10 ^ (-3) V

i.e. double the answer
 
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Masafi said:
I had 2 questions:

1. My textbook derives that the equation from lenz's and faraday's law

emf = - d(N*flux)/dt
= B * dA/dT

where dA/dt = length * speed
That last step is a special case where you have a wire sweeping out an area. Note that the wire moves at a single speed.

However, why does the N value disappear in the new equation?
Presumably there is a single moving wire sweeping out an area.

Also, this question is given after:

2. A metal propeller rotates in a verical plane with angular vel 85 rad per sec. The length of the propeller from tip to tip is 2.5m. Calculate emf generated between centre and tip of properller. The horizontal component of Earth's magnetic field is 22 x 10^(-6) T (micro Tesla)

The answer is 1.5 x 10^(-3) V. I don't get this.

I did emf = B * dA/dt

dA/dt = length * speed
= 1.25 * (1.25 * 85)

which gives emf = 2.9 x 10 ^ (-3) V

i.e. double the answer
You took the speed of the propeller as equal to the speed of the tip. But the speed varies from zero at the center to a maximum at the tip. (What's the average speed?)
 
Doc Al said:
That last step is a special case where you have a wire sweeping out an area. Note that the wire moves at a single speed.


Presumably there is a single moving wire sweeping out an area.


You took the speed of the propeller as equal to the speed of the tip. But the speed varies from zero at the center to a maximum at the tip. (What's the average speed?)

Thanks a lot :)
 
I personally don't understand how this question is done.
If I look at the formula and then at the question there is nothing in common?
 
so we know v = wr = 85 * 1.25 = 106.25 m/s
swept area = length * speed = 1.25 * 106.25 = 132.8

emf = (B*A*n)/t
emf = (132.8)/t
... how do I contnue (is this correct?)
 

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