Induced EMF in a Triangle: Determining EMF and External Force

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Homework Help Overview

The problem involves determining the induced electromotive force (emf) in a circuit formed by a conducting bar moving within a magnetic field, as well as calculating the external force required to maintain the bar's motion. The context is rooted in electromagnetic principles, specifically Faraday's Law and the Hall Effect.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of Faraday's Law and the Hall Effect to derive the induced emf, noting discrepancies in sign conventions. Questions arise regarding the appropriateness of expressing variables in terms of time or position, particularly in relation to the geometry of the triangle.

Discussion Status

Some participants have provided insights into the sign conventions for the forces and emf, while others are exploring the implications of expressing variables as functions of time or position. The discussion is ongoing, with no explicit consensus reached on the correct approach or expressions.

Contextual Notes

Participants note the complexity introduced by the triangular shape of the setup, which affects how variables can be expressed. There is also mention of unspecified directions for current flow, which may influence the interpretation of signs in the equations.

SataSata
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Homework Statement


Magnetic Field B is going into the plane.
Bar is moving to the right with velocity v.
Neglect resistance of the conducting bar and all contacts.
a.) Determine the induced emf in the circuit.
b.) To maintain the uniform motion of the conductive bar, there must be an external force Fapp to pull the conductive bar. How much should Fapp be?
upload_2016-4-1_16-37-58.png


Homework Equations


Let the length of conducting bar in the triangle be ##l##
Hall Effect: ##emf = Blv ##
Faraday: ##emf = -d\Phi/dt##
##\Phi = BA##
##A=xl/2##
##l=xtan\theta##
##F_B=IlB##

The Attempt at a Solution


Using Faraday's Law:
##emf = -d\Phi/dt = -BdA/dt##
##dA/dt = dA/dx \times dx/dt##
##dA/dt = vxtan\theta##
##\therefore emf = -Bvxtan\theta##
Or, Using Hall Effect:
##emf = Blv = Bvxtan\theta##
Next, ##F_app = -F_B##
## Current I = emf/R = -Bvxtan\theta/R##
##F_app= IlB = B^2vx^2tan^2\theta/R##

Can anybody check if my attempt is correct? Are all the negative signs correct?
Faraday's Law and Hall Effect give different signs. Which one is correct?
Fapp sign is supposed to be positive or negative?
 
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SataSata said:
Faraday's Law and Hall Effect give different signs. Which one is correct?
Depends on the unspecified direction of your current flow. You don't need that direction, however.
I would choose a positive sign for the force needed to pull the bar, which means the induction leads to a negative force. But that is just an aesthetic choice (have force and velocity with the same sign convention if v is positive), the physical direction of the force is given in the problem statement already.
 
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Thank you for your reply mfb.
But is it right to express my answer in terms of x? Since x is a function of time, I can simply write it as x(t) and so emf and Fapp will both be a function of time too. However, the question simply asked for emf induced and Fapp, which caused me to doubt my answers.
In a non-triangle shape like a rectangle that's extending in length, the breadth is a constant and hence I can write my answer with it. But in this case, all sides of the triangle are varying and so I'm not sure how to express my answers.
 
Well, both depend on time here. Expressing them as function of x or t should be fine.
 
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