Calculating Energy: 5.8Kg Body from 2.3m/s to 1.5m/s

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SUMMARY

The discussion focuses on calculating the energy derived from slowing a body with a mass of 5.8 kg from a velocity of 2.3 m/s to 1.5 m/s. The key formula used is the kinetic energy equation, KE = (1/2) * m * v^2. Participants clarify that the change in kinetic energy must be calculated by finding the kinetic energy at both velocities and then determining the difference. This approach effectively provides the energy lost during the deceleration process.

PREREQUISITES
  • Kinetic energy formula: KE = (1/2) * m * v^2
  • Understanding of mass and velocity concepts
  • Basic algebra for manipulating equations
  • Concept of energy conservation in physics
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Homework Statement


How much energy could be derived from slowing a body of mass 5.8Kg from 2.3m/s to 1.5m/s?


Homework Equations





The Attempt at a Solution


I don't even know what formula to use here so if someone could give me a couple of formlula that would be good to start with. thanks
 
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You could find the change in kinetic energy (energy of motion). Ke = (1/2)*m*v^2
 
I have tried that and it doesn't work for me??
 

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