How Far Does the Ball Land from the Pole?

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Eitan Levy
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Homework Statement


Diagram of a rotating frame: a vertical pole with a horizontal arm of length b at the top, a vertical length l hanging down from the arm's end to a box labelled CAR, and a circular rotation arrow at the pole's base above the ground.

l=2m
b=1.5m
The mass of the chair is 5kg.
A boy with a mass of 50kg sits on the chair.
The distance of the chair from the pole is 3m, and it spins around it horizontally with a radial velocity of 1.95 rad/s.
The boy drops a ball at some moment, what would be its distance from the pole when it hits the ground if the distance of the chair from the ground when it doesn't spin is 0.5m?

Homework Equations

The Attempt at a Solution


First I drew this:
Hand-drawn diagram of a swing geometry: a vertical pole on the left with a horizontal bar at the top, a vertical drop of 1.323m labelled on the left and again beside a slanted line, a 2m slanted segment at 41.4° to a horizontal 1.5m bar, and a 1.177m vertical measurement on the lower pole.

ω2r=v2/r
v=5.85m/s (The velocity of the ball when the boy drops it, all of it horizontal.
Then -1.177=-5t2 (The times it will take the ball to hit the ground).
t=0.4851
Δx=vt=2.8378m
Total distance from the pole: √(3^2+2.8378^2)=4.13m
The answer in the book is 12.42m, I have no idea how they could possible reach to such a large distance.
 
Attachments
  • Diagram of a rotating frame: a vertical pole with a horizontal arm of length b at the top, a vertical length l hanging down from the arm's end to a box labelled CAR, and a circular rotation arrow at the pole's base above the ground.
    upload_2017-12-18_16-3-19.png
    2.7 KB · Views: 926
  • Hand-drawn diagram of a swing geometry: a vertical pole on the left with a horizontal bar at the top, a vertical drop of 1.323m labelled on the left and again beside a slanted line, a 2m slanted segment at 41.4° to a horizontal 1.5m bar, and a 1.177m vertical measurement on the lower pole.
    upload_2017-12-18_16-14-51.png
    1.7 KB · Views: 500
Can you show in detail how you got the initial velocity, 5.85 m/s? It doesn't match the numbers in your figure.
 
kuruman said:
Can you show in detail how you got the initial velocity, 5.85 m/s? It doesn't match the numbers in your figure.
It says that the TOTAL distance of the chair from the pole while it spins at this radial velocity is 3m. Therefore r=3m.
 
I see. OK, I cannot find anything wrong with your answer. One could get an answer close to the one in the book if one used ω2r for v instead of ωr.
 
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kuruman said:
I see. OK, I cannot find anything wrong with your answer. One could get an answer close to the one in the book if one used ω2r for v instead of ωr.
Alright, thank you!