Calculating Energy Absorbed in a Collision: Quad vs. Tree

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Discussion Overview

The discussion revolves around calculating the average force exerted on a tree by a quad during a collision and determining the energy absorbed in that collision. Participants explore the application of physics concepts related to momentum and kinetic energy in the context of a homework problem.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant calculates the force on the tree using the formula F = M(v/t) and arrives at a value of 18,198.8 lbs.
  • Another participant suggests using impulse and momentum to derive the force, stating that force equals the change in speed multiplied by mass divided by time.
  • Several participants calculate the kinetic energy before the collision using the formula KE = 0.5 * mass * (velocity)^2, arriving at a value of 5332.24 ft-lbf.
  • There is a discussion about whether the tree absorbs all the kinetic energy, with one participant asserting that since the quad comes to a stop, the tree must absorb all the energy.
  • Another participant notes that both the tree and the quad absorb energy during the collision, suggesting a more complex interaction.
  • Participants discuss the relevance of significant figures in their calculations, with some indicating that rounding to the nearest whole number is acceptable.

Areas of Agreement / Disagreement

Participants generally agree on the method for calculating kinetic energy and the force involved in the collision, but there is disagreement regarding how much energy is absorbed by the tree versus the quad. The discussion remains unresolved on the specifics of energy absorption during the collision.

Contextual Notes

There are limitations regarding the assumptions made about the collision, such as whether the quad stops completely and how energy is distributed between the quad and the tree. The discussion also reflects uncertainty about the appropriate units for energy in this context.

jbm1939
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Homework Statement


A 400 lb quad hits a tree moving at 20 mph, if the time of impact is .02 seconds what would the average force be on the tree? Also how much energy would be absorbed in the collision?

Homework Equations


I was able to solve the first part of the question, the force on the tree. I will put my work on that part below, what I am confused about is how to start the part about finding how much energy was absorbed. Any help would be greatly appreciated.

The Attempt at a Solution


20mph = 29.333 fps
F = M(v/t)
so
FΔT=MΔT
F(.02) = (400lbs/32.2ft/s) * (29.3 ft/s)
F = 18,198.8 lbs
 
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Assuming the object stops completely after collision:

For the force:
force*impact time = impulse;
impulse = change in momentum
momentum = speed * mass

therefore: force = (change in speed)*mass/time

For the energy:
kinetic energy = 0.5 * mass * (velocity)^2
Calculate the change in kinetic energy before and after and you are set.
 
so for KE=.5mv^2
=.5(400/32.2)(29.3)^2
= 5332.24
so would this be the amount absorbed by the tree in the impact? their would be no KE after the collision because v=0, so the tree has to absorb all that energy? am i correct with this deduction?
 
jbm1939 said:
so for KE=.5mv^2
=.5(400/32.2)(29.3)^2
= 5332.24
so would this be the amount absorbed by the tree in the impact? their would be no KE after the collision because v=0, so the tree has to absorb all that energy? am i correct with this deduction?
As far as I can tell, that is correct. I didn't actually do the calculations because I am not really familiar with imperial units, also, I am not sure what unit of energy that is going to produce, but I trust that your calculations is accurate.
 
thank you 24forChromium! its getting to the end of the semester here and my brain is overwhelmed at the moment. this forum is awesome for an extra set of eyes to help you see what you've overlooked.
 
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jbm1939 said:
so would this be the amount absorbed by the tree in the impact?
Remember, the original question is: "How much energy would be absorbed in the collision?" Both the tree and the quad absorb part of this energy.

Also, I assume your instructor isn't a stickler about significant figures...
 
No he did not say anything about significant figures, I generally just round to the nearest whole number. The question just say how much energy would be absorbed in the collision, so that would be the total amount of kinetic energy correct? What is derived from 1/2mv2?
 
jbm1939 said:
The question just say how much energy would be absorbed in the collision, so that would be the total amount of kinetic energy correct? What is derived from 1/2mv2?
Correct.

About significant figures, the problem implies no more than 3 are suitable, giving an answer of 5330 ft-lbf.
Adding significant figures implies accuracy that simply isn't there.
 
Thanks insightful, I'll fix that on my problem.
 

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