Calculating Energy Transfer for 75kg Boy Sliding Down Hill

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SUMMARY

The discussion focuses on calculating the thermal energy transfer for a 75 kg boy sliding down a 30-degree hill that is 70 m long, reaching a speed of 15 m/s at the bottom. The relevant equations include kinetic energy (KE = 1/2Mv²) and potential energy (PE = Mgh). By determining the initial potential energy and the final kinetic energy, the thermal energy shared between the hill's surface and the boy's pants can be calculated as the difference between these two energy states.

PREREQUISITES
  • Understanding of basic physics concepts such as potential energy (PE) and kinetic energy (KE).
  • Familiarity with energy conservation principles in mechanical systems.
  • Ability to perform calculations involving trigonometric functions for inclined planes.
  • Knowledge of the equations of motion, particularly d = (vf² - vi²) / 2a.
NEXT STEPS
  • Calculate the initial potential energy using PE = Mgh for the given height of the hill.
  • Determine the final kinetic energy using KE = 1/2Mv² with the boy's final speed.
  • Analyze the energy loss to thermal energy by finding the difference between initial potential energy and final kinetic energy.
  • Explore the implications of energy transfer in friction scenarios, particularly in sliding motion.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy transfer, as well as educators looking for practical examples of energy conservation in real-world scenarios.

phys1618
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Homework Statement



75 kg boy, starting from rest, slides down a 30 degrees hill htat is 70 m long. He arrives a thet bottom with a speed of 15 m/s. How much thermal energy has been shared btwn the surface of the hill and the seal of his pants

Homework Equations


d=(vf2-vi2)/2a
KE=1/2Mv2
change of ENERGYsystem=constant
PEi +KEi=PEf + KEf
PE=Mgh



The Attempt at a Solution


I have no clue to figure this out...please help by explaining the steps..Many thanks!
 
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phys1618 said:

Homework Statement



75 kg boy, starting from rest, slides down a 30 degrees hill htat is 70 m long. He arrives a thet bottom with a speed of 15 m/s. How much thermal energy has been shared btwn the surface of the hill and the seal of his pants

Homework Equations


d=(vf2-vi2)/2a
KE=1/2Mv2
change of ENERGYsystem=constant
PEi +KEi=PEf + KEf
PE=Mgh



The Attempt at a Solution


I have no clue to figure this out...please help by explaining the steps..Many thanks!

Figure what his PE was. Then figure what his KE is at the bottom. The difference went into warming his behind.
 

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