Calculating Entropy Change in a Lead-Lake System

Click For Summary

Homework Help Overview

The discussion revolves around calculating the entropy change in a system involving a 5.0-kg piece of lead at a high temperature placed in a lake at a significantly lower temperature. Participants are tasked with determining the entropy changes for the lead, the lake, and the universe, while addressing the potential lack of necessary data for the lake's size.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formula for calculating entropy change for the lead and express uncertainty regarding the lake's entropy change. There are attempts to confirm calculations and question the adequacy of the provided data.

Discussion Status

Some participants have confirmed their calculations for the lead's entropy change and are exploring how to calculate the lake's entropy change based on heat transfer. There is an ongoing examination of the total entropy change for the universe, with some expressing skepticism about the book's answers.

Contextual Notes

Participants note the absence of information regarding the lake's size, which may impact the calculations for the lake's entropy change. The assumption that the lake's temperature remains constant is also under discussion.

Chemmjr18
Messages
51
Reaction score
1

Homework Statement



A 5.0-kg piece of lead at a temperature of is 600 Celsius placed in a lake whose temperature is 15 Celsius. Determine the entropy change of (a) the lead piece, (b) the lake, and (c) the universe.

mass of lead=5 kg
initial temperature of lead=873.15 K
final temperature of lead=288.15 assumed that the temperature of lake won't noticeably change)
heat capacity of lead=128 J/(kg⋅K)

Homework Equations


For the lead,
ΔS=mass of lead⋅heat capacity of lead⋅ln(final temperature/initial temperature)

For the lake and the universe I am not sure where to begin.

The Attempt at a Solution


For the lead I got
ΔS=-710 J/K

The books answer is ΔS=-540 J/K for the lead. I feel like the book isn't giving all of the necessary data to solve this problem (i.e. the size of the lake).
 
Physics news on Phys.org
Chemmjr18 said:

Homework Statement



A 5.0-kg piece of lead at a temperature of is 600 Celsius placed in a lake whose temperature is 15 Celsius. Determine the entropy change of (a) the lead piece, (b) the lake, and (c) the universe.

mass of lead=5 kg
initial temperature of lead=873.15 K
final temperature of lead=288.15 assumed that the temperature of lake won't noticeably change)
heat capacity of lead=128 J/(kg⋅K)

Homework Equations


For the lead,
ΔS=mass of lead⋅heat capacity of lead⋅ln(final temperature/initial temperature)

For the lake and the universe I am not sure where to begin.

The Attempt at a Solution


For the lead I got
ΔS=-710 J/K

The books answer is ΔS=-540 J/K for the lead. I feel like the book isn't giving all of the necessary data to solve this problem (i.e. the size of the lake).
I confirm your 710 value.

How much heat is transferred to the lake? With this amount of heat transferred, if the lake is considered an ideal reservoir at 15 C, what is its change in entropy? What is the sum of the entropy change of the lead and the lake?
 
Last edited:
  • Like
Likes   Reactions: Chemmjr18
Chestermiller said:
I confirm your 710 value.

How much heat is transferred to the lake? With this amount of heat transferred, if the lake is considered an ideal reservoir at 15 C, what is its change in entropy? What is the sum of the entropy change of the lead and the lake?

Thanks for your help. I guess the book is wrong (which isn't surprising). For the lake, I got ΔS=1300 J/K and for the universe, I got ΔS=590 J/K.
 
Chemmjr18 said:
Thanks for your help. I guess the book is wrong (which isn't surprising). For the lake, I got ΔS=1300 J/K and for the universe, I got ΔS=590 J/K.
Confirmed.
 
  • Like
Likes   Reactions: Chemmjr18
Chestermiller said:
Confirmed.
Thanks for the help!
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 16 ·
Replies
16
Views
3K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 23 ·
Replies
23
Views
4K
  • · Replies 7 ·
Replies
7
Views
6K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
6K