Calculating Equivalent Resistance of Resistor Network

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SUMMARY

The equivalent resistance of the given resistor network can be calculated using the formula Req = 1/2 [(4RtRl + Rt^2)^(0.5) + Rt]. The discussion highlights the approach of treating the infinite circuit by simplifying the resistors into a recursive formula. By assuming the resistance of the remaining circuit as R and applying the formula R*Rl/(R+Rl) + Rt = R, one can derive the equivalent resistance effectively.

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Homework Statement



Show that the equivalent resistance is Req = 1/2 [(4RtRl + Rt^2)^(.5) + Rt]
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Homework Equations


The Attempt at a Solution



So far all I can get is Req = Rt + Rl Rt/(Rt+Rl) from the first three resistors starting from the left. I suppose I could take that and add it to the next branch Rl Rt/(Rt+Rl), but that would appear to go on to infinity as opposed to stopping at a nice number.

Does anyone have any hints on finding the eq. resistance?
 
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I believe by recursion.

Everything to the right of RL is parallel with RL, and in series with RT.
 
Since this is an infinite circuit, ignore the first rt and rl, and assume the resistance of the rest to be R. This give you:

R*rl/(R+rl) +rt=R. As the resistance of the total circuit is also R. Solve for R to get your answer.
 

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