How Do You Calculate Thevenin Equivalent Circuit Without a Load Resistor?

Click For Summary

Homework Help Overview

The discussion revolves around finding the Thevenin equivalent circuit without a load resistor, specifically focusing on the analysis of the circuit's components and configurations.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to apply a series of steps to determine the Thevenin equivalent but expresses confusion regarding a specific symbol for a current source and its impact on the circuit. Some participants question the assumption that all resistors are in parallel and suggest clarifying the treatment of independent sources.

Discussion Status

Participants are providing clarifications on circuit symbols and discussing the proper approach to suppressing independent sources. There is an ongoing exploration of the original poster's reasoning and assumptions without reaching a consensus.

Contextual Notes

The original poster's calculations assume a specific configuration of resistors and the presence of a current source, which has led to some confusion regarding the circuit analysis. The discussion highlights the need for clarity on circuit symbols and the treatment of sources in Thevenin's theorem.

Alexander Max
Messages
3
Reaction score
0

Homework Statement


upload_2015-1-5_22-42-49.png

I am to find the thevenin equivalent circuit without the load resistor (to the left of terminals a &b

Homework Equations



From class notes:
1- Remove the load resistor
2- find the open circuit voltage across a & b
3- Remove all voltage sources (replace with short circuit)
4- Detrmine the equivalent circuit resistance across the break
5- Form an equivalent circuit

The Attempt at a Solution



I have not come across the symbol that looks like an 8 with the 2amps next to it so far, and i don't understand how this will effect my circuit, is it a voltage source, how will it effect the resistors?
Without acknowledging it,
my resistors are all in parralel so Restance total is
1/RT = 1/R1 + 1/R2 + 1/R3
1/RT = 1/4 + 1/12 + 1/1
1/RT = 3/12 + 1/12 + 12/12
1/RT = 16/12
RT = 12/16
RT = 0.75

32v/0.75 ohms = 42.667 Amps
Vab = 32 - 1x42.667Amps = -10.667 Volts

Resistance looking in has already been calulated as 0.75 ohms

 

Attachments

  • upload_2015-1-5_22-42-3.png
    upload_2015-1-5_22-42-3.png
    49.5 KB · Views: 620
Physics news on Phys.org
Hello Alex, and welcome to PF :)

The 2A thingy is a (slightly outdated) symbol for a current source.

I don't see how you can consider all R as parallel.
 
Hi Alexander Max, Welcome to Physics Forums.

As BvU stated, the two-circle symbol represents a current source. It's a bit outmoded as a schematic symbol, but it still crops up fairly often.

Allow me to amend your algorithm's item 3 a bit, since in its given form it doesn't address current sources:

3 - Suppress all independent sources: Replace voltage sources with a short circuit and all current sources with an open circuit (simply remove them entirely).
 
Thank you for your help!
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
10
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
9
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
15
Views
3K