Calculating Escape Velocity for a Small Asteroid with Given Initial Velocity

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SUMMARY

The escape velocity for a small asteroid is established at 28 m/s, while an object is thrown from the asteroid at an initial velocity of 39 m/s. The relevant equations include the conservation of energy equation, which simplifies to 0 = 0.5mv² - GM/r, and the escape velocity formula Vi = sqrt(2GM/r). The challenge lies in determining the final speed of the object without knowing the asteroid's mass or radius, highlighting the need for additional equations or relationships to connect these variables.

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  • Understanding of classical mechanics and conservation of energy principles
  • Familiarity with escape velocity calculations
  • Knowledge of gravitational potential energy and kinetic energy equations
  • Basic algebra and manipulation of equations
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  • Explore the derivation of escape velocity equations in astrophysics
  • Learn about gravitational potential energy and its role in motion equations
  • Investigate numerical methods for solving equations with unknown variables
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Students in physics or astronomy, educators teaching mechanics, and anyone interested in celestial dynamics and escape velocity calculations.

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Homework Statement


The escape speed from a very small asteroid is only 28 m/s. If you throw a rock away from the asteroid at a speed of 39 m/s, what will be its final speed?
Vesc= 28m/s
Vi= 39 m/s

Homework Equations


Ks,f + Ke,f + Uf = Ks,i + Ke,i + Ui +W
Vi=sqrt(2GM/r)

The Attempt at a Solution



Well I know the first equation gets simplfied to
0=.5mv^2 + (-GM/r)
Vi=sqrt(2GM/r)

But I don't have radius or mass of my asteroid and I don't have any equations that incorporate the final velocity...

But I can't figure out how to
 
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How can you relate the asteroid's escape velocity to the values you're looking for?
 

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