Calculating First Ionization Energy

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SUMMARY

The discussion focuses on calculating the first ionization energy of lithium (Li) using Hess's law and bond enthalpy values. The relevant reactions include the formation of lithium fluoride (LiF) and the dissociation of fluorine (F2) into fluorine atoms. The calculated first ionization energy of Li is determined to be 520 kJ/mol, aligning with option (a). The user seeks clarification on the correct application of Hess's law to derive this value accurately.

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Homework Statement


I have an exam on Monday and do not know how to do this example problem.

Use the following information to calculate the first ionization energy of Li.
LiF(s) → Li+(g) + F −(g) 1050 kJ/mol LiF
Li(s) + ½ F2(g) → LiF(s) −617 kJ/mol Li
F2(g) → 2 F(g) 160 kJ/mol F2
Li(s) → Li(g) 161 kJ/mol Li
F(g) → F −(g) −328 kJ/mol F

(a) 520 kJ/mol Li
(b) 440 kJ/mol Li
(c) 426 kJ/mol Li
(d) 346 kJ/mol Li
(e) 216 kJ/mol Li

The answer is a but I can't figure out how to get it. If you could show me the process I would greatly appreciate it.

Homework Equations


H=Bonds Broken - Bonds Formed

The Attempt at a Solution


617 = 160 + 161 +1050 + x - 328
x = 426
I know this method isn't right because 1. It makes no sense 2. It doesn't follow the bond enthalpy formula
 
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How can you combine the reactions given to have a balanced equation with Li(g) as a reactant and Li+(g) as a product, and all the others as spectators?
 
Don't go for bonds, use Hess law (which is basically what PhaseShifter suggests).

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