Calculating Flux with a Constant Vector Field on a Disk of Radius 4

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Homework Help Overview

The problem involves calculating the flux of a constant vector field through a disk of radius 4, which is oriented perpendicular to both the vector field and the y-axis. The total flux is specified to be 5.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of the disk's orientation and the relationship between the vector field and the surface area. Questions arise about the direction and magnitude of the vector field necessary to achieve the specified flux.

Discussion Status

There is an ongoing exploration of the problem's requirements, with some participants suggesting that the field must be perpendicular to the surface for the flux calculation. Others are clarifying the implications of the disk's orientation and the nature of the vector field.

Contextual Notes

Participants note that the problem's constraints regarding the orientation of the disk and the vector field may lead to specific interpretations about the direction of the field. There is also mention of notation used for vector fields, which may influence how participants express their understanding of the problem.

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Homework Statement


Find the constant vector field F giving the flux of 5 trough the surface S, a disk of radius 4 perpendicular to both F and the y-axis, and oriented away from the origin.

Homework Equations

The Attempt at a Solution


I have gone through several articles on the web and searched through my textbook but I can't seem to find any relevant information to assist me making sense of the question.
 
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The magnitude will be such that over the area of the surface to total flux will be 5. the direction will be based on the orientation of the disk--perpendicular.
 
So what is this question even asking? We haven't really even talked about vector fields
 
I think it is asking you to determine the magnitude and direction such that the total flux is 5.
If the field is perpendicular to the surface, the flux is just the magnitude of the field times the area of the surface. If it is skewed, then there is a penalty based on the angle of incidence.
I am not sure what the direction is, since all you have given about the disk is that it is perpendicular to both the y-axis and the field.
a circle perpendicular to the y-axis will be entirely in the x-z plane.
You could just assume that the field is entirely y-directed for a simple example.
 
RUber said:
I am not sure what the direction is, since all you have given about the disk is that it is perpendicular to both the y-axis and the field.

The information given is equivalent to "the normal to the disc is parallel to both the field and the y-axis". Thus the field is parallel to the y-axis.
 
Thanks pasmith. I was adding additional dimensions in my mind.
In 3D, a 2-dimensional shape perpendicular to 2 vectors implies that both vectors are in the 3rd dimension.
 
So all thank you very much. But one last question, when writing a vector field what is proper notation or notation that is used frequently?
 
Often you will see either ## a\hat x + b\hat y + c\hat z## or ## a\hat i + b\hat j + c\hat k## for the standard three dimensions.
A constant vector field is just one vector repeated many times (constant coefficients a, b, c). A variable field will have variables for a , b , and c which may depend on x, y, z, t, or whatever.
 

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