Calculating Force Exerted on Horizontal Beam in Fig. 11-25

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SUMMARY

The discussion centers on calculating the forces acting on a horizontal beam depicted in Fig. 11-25, which weighs 170 N with its center of gravity located at its center. The tension in the supporting cable is determined to be 641.66 N, while the horizontal force exerted on the beam at the wall is calculated to be 513.33 N. To find the upward vertical component of the force, participants suggest summing the forces in both horizontal and vertical directions, leading to three equations with three unknowns. The solution involves applying the principles of static equilibrium and moment summation about the wall.

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The horizontal beam in Fig. 11-25 weighs 170 N, and its center of gravity is at its center.

11-25.gif


(a) Find the tension in the cable.
641.66 N
(b) Find the horizontal and vertical components of the force exerted on the beam at the wall.
513.33 N (to the right)
? N (upwards)

Any tips on how I would get the upward component of the force?
 
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If you sum the forces in the horizontal direction you will have two unknowns, the horizontal component of tensions and the horizontal reaction force on the beam.

The exact same thing can be said about the vertical forces...

This leaves you with, three unknowns because you can relate the tension in the vertical to the tension in the horizontal given the geometry in this problem.

To get one more equation, I would sum moments using the wall as a base point.

If you are looking for a more detailed response, show some work next time.

In the end you will have 3 equations and 3 unknowns, all of which are linear equations and can be solved many ways.
 

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