Calculating Force in a Rifle-Bullet System

Click For Summary
SUMMARY

The discussion focuses on calculating the force exerted on a rifle by a bullet in a rifle-bullet system. The rifle weighs 50.0 N, and the bullet has a mass of 25.0 g, exiting the barrel at a muzzle velocity of 320 m/s. The participant initially used the equation v² = v₀² + 2ax to find acceleration, resulting in an incorrect force calculation of 17067 N. The correct approach involves ensuring proper unit conversions and applying Newton's second law (F = MA) accurately.

PREREQUISITES
  • Understanding of Newton's second law (F = MA)
  • Familiarity with kinematic equations, specifically v² = v₀² + 2ax
  • Basic knowledge of unit conversions, particularly between grams and kilograms
  • Ability to perform calculations involving force, mass, and acceleration
NEXT STEPS
  • Review unit conversion techniques, especially converting grams to kilograms for mass calculations
  • Study the application of kinematic equations in projectile motion scenarios
  • Explore detailed examples of force calculations in various physics problems
  • Learn about the implications of acceleration on force in different contexts, such as firearms
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of force calculations in real-world applications.

*intheclouds*
Messages
19
Reaction score
0

Homework Statement



A rifle weighs 50.0 N, and its barrel is 0.750 m long. It shoots a 25.0 g bullet, which leaves the barrel at a speed (muzzle velocity) of 320 m/s after being uniformly accelerated. What is the magnitude of the force exerted on the rifle by the bullet?

Homework Equations


F=MA
w=mg
v=v0+at
v2=v02+2ax



The Attempt at a Solution


I wasn't totally sure of what I was doing, but this is what I did:
I used the equation: v2=v02+2ax and did-- 3202=0+2(a)(.750) and I got 68266.67 m/s2. I don't know if I did this right, or if I even used the right equation.

Then I used the F=MA equation. F=.25(68266.67) to get 17067 N, but when I typed in that answer to Webassign, it was wrong.



Any help would be greatly apprecitated. Thank you!
 
Physics news on Phys.org


*intheclouds* said:

Homework Statement



A rifle weighs 50.0 N, and its barrel is 0.750 m long. It shoots a 25.0 g bullet, which leaves the barrel at a speed (muzzle velocity) of 320 m/s after being uniformly accelerated. What is the magnitude of the force exerted on the rifle by the bullet?

Homework Equations


F=MA
w=mg
v=v0+at
v2=v02+2ax



The Attempt at a Solution


I wasn't totally sure of what I was doing, but this is what I did:
I used the equation: v2=v02+2ax and did-- 3202=0+2(a)(.750) and I got 68266.67 m/s2. I don't know if I did this right, or if I even used the right equation.

Then I used the F=MA equation. F=.25(68266.67) to get 17067 N, but when I typed in that answer to Webassign, it was wrong.



Any help would be greatly apprecitated. Thank you!

Check your units on what I bolded in your post. It's good to write out the units of each quantity in your equations, to make sure you don't make mixed-units errors like this. I've found that habit of carrying along units in my calculations to be a huge help.

Welcome to the PF!
 


That worked! Thank you so much! You are amazing! =]
I generally get the concepts, but then I make silly little mistakes like that and I can't find where I went wrong.

And thanks for the welcoming!
 

Similar threads

Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
14
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
6K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 9 ·
Replies
9
Views
4K
Replies
1
Views
7K
Replies
1
Views
2K