What is the force exerted on a bullet leaving a rifle?

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SUMMARY

The force exerted on a 5.0g bullet leaving a rifle with a speed of 320 m/s can be calculated using Newton's second law, represented by the equation ΣF = ma. The bullet travels down a 0.82 m long barrel, and applying the work-energy theorem, W = ΔE_k, provides a straightforward method to determine the force. The calculations yield a constant force acting on the bullet during its acceleration within the barrel.

PREREQUISITES
  • Understanding of Newton's second law (ΣF = ma)
  • Familiarity with the work-energy theorem (W = ΔE_k)
  • Basic knowledge of kinematics and dynamics
  • Ability to perform unit conversions (grams to kilograms)
NEXT STEPS
  • Calculate the acceleration of the bullet using kinematic equations
  • Explore the implications of constant force on bullet trajectory
  • Investigate the effects of barrel length on bullet velocity
  • Learn about energy conservation in projectile motion
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Physics students, mechanical engineers, and anyone interested in ballistics and the dynamics of projectiles.

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Homework Statement


A 5.0g bullet leaves the muzzle of a rifle with a speed of 320 m/s. What force (assumed constant) is exerted on the bullet while it is traveling down the 0.82 m long barrel of the rifle?


Homework Equations


\SigmaF=ma


The Attempt at a Solution


 
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It might be simpler to use the work-energy theorem here:

W=\Delta E_k
 

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