Calculating Force Needed to Pull Sled with 210kg Load

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SUMMARY

The discussion focuses on calculating the force required to pull a sled with a load of 210 kg on a snowy surface, where the coefficient of friction is 0.095. Using Newton's second law, the force (F) is determined by the equation F = m*a + Ff, where Ff is the frictional force. The final calculation yields a force of 223.0095 N, confirming the accuracy of the solution provided. This demonstrates the application of physics principles in real-world scenarios involving sled dynamics.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Basic knowledge of friction coefficients
  • Ability to perform calculations involving mass and acceleration
  • Familiarity with gravitational acceleration (9.81 m/s²)
NEXT STEPS
  • Study the implications of varying friction coefficients on sled dynamics
  • Explore advanced applications of Newton's laws in different contexts
  • Learn about the effects of acceleration on force calculations
  • Investigate the role of gravitational forces in various physical scenarios
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in the practical applications of force calculations in real-world situations.

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Homework Statement


Sled dog to pull on a snowy sleigh horizontal road, the mass of its load is 210 kg. Snow and sleigh runners movement between the friction coefficient is 0.095. Dogs sleigh force exerted by the horizontal. acceleration of 0.13 m/s2? Gravitational acceleration is 9.81 m/s2.

Homework Equations


How much force as the dogs pull the sled

The Attempt at a Solution


Newton second law and by projection:
F-Ff=m*a
F=m*a+Ff
F=210*0.13+0.095*210*9.81
F= 223.0095 N
 
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chawki said:
Newton second law and by projection:
F-Ff=m*a
F=m*a+Ff
F=210*0.13+0.095*210*9.81
F= 223.0095 N

looks good! :smile:
 
That is correct!
 

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