Calculating Force of Bat on Ball: Physics Homework Solution

  • Thread starter Thread starter futureteacher
  • Start date Start date
  • Tags Tags
    Ball Force
Click For Summary
SUMMARY

The average force exerted by the bat on a 0.145 kg baseball, pitched at 37 m/s and hit at 51.5 m/s over a contact time of 3.5 x 10-3 seconds, is calculated using the formula F = m(vfinal - vinitial) / Δt. The correct change in velocity should account for the direction of the forces, resulting in a total change of 88.5 m/s (51.5 + 37.0 m/s). The accurate average force is approximately 3,600 N, not 600 N as initially calculated.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Familiarity with momentum and its vector nature
  • Basic knowledge of kinematics and equations of motion
  • Ability to perform calculations involving mass, velocity, and time
NEXT STEPS
  • Study the concept of vector quantities in physics
  • Learn about momentum conservation in collisions
  • Explore advanced applications of Newton's laws in sports physics
  • Practice similar problems involving force calculations in different contexts
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to explain force and momentum concepts in practical scenarios.

futureteacher
Messages
2
Reaction score
0

Homework Statement


A 0.145 ball is pitched at 37 m/s and is hit on a horizontal line drive at 51.5 m/s. If the contact time between the ball and the bat is 3.5x10-3 seconds what is the avg force between the bat and the ball during contact.

Homework Equations


P=mv
[tex]\Sigma[/tex]F=[tex]\Delta[/tex]P/[tex]\Delta[/tex]T

mfinal*vfinal-minitial*vinitial/[tex]\Delta[/tex]Time

factor out m (mass)
m(vfinal-vinitial)/[tex]\Delta[/tex]t

The Attempt at a Solution


0.145kg(51.5m/s-37.0m/s)/(3.5*10-3)

i get 600N but my webwork says that not right i have no idea what I am doing wrong
 
Physics news on Phys.org
futureteacher said:

Homework Statement


A 0.145 ball is pitched at 37 m/s and is hit on a horizontal line drive at 51.5 m/s. If the contact time between the ball and the bat is 3.5x10-3 seconds what is the avg force between the bat and the ball during contact.

Homework Equations


P=mv
[tex]\Sigma[/tex]F=[tex]\Delta[/tex]P/[tex]\Delta[/tex]T

mfinal*vfinal-minitial*vinitial/[tex]\Delta[/tex]Time

factor out m (mass)
m(vfinal-vinitial)/[tex]\Delta[/tex]t

The Attempt at a Solution


0.145kg(51.5m/s-37.0m/s)/(3.5*10-3)

i get 600N but my webwork says that not right i have no idea what I am doing wrong
The change in velocity is 51.5 + 37.0 m/s. The ball is hit in the opposite direction to the pitch.

Don't forget that force and momentum are vector quantities. The definition of force is:

[tex]\vec F = \sum \vec F_i = \frac{d\vec p}{dt}[/tex]

AM
 
Last edited:

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
7K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
5
Views
3K