(adsbygoogle = window.adsbygoogle || []).push({}); _{1. The problem statement, all variables and given/known data We place three charges in the corners of the equilateral triangle; the size of the sides is 1 m. Charges are of sizes: e1, e2 = −2e1, and e3 = 3e1, where e1 = 10 ^-6 As. What is the force on the first (second, third) charge and in which direction are they showing? http://item.slide.com/r/1/20/i/uNrFtWB4tT_sS7zkuV1ExJS_gf3980kJ/ [Broken] http://item.slide.com/r/1/130/i/1G12EjLq5D8Lo4lU8yYKxmOQfVTQfoSl/ [Broken] http://item.slide.com/r/1/142/i/dpHAZtcg7j-o-U_uDNFiH60YH-Do8Dwr/ [Broken] 2. Relevant equations F= k[q(1)q(2)/ d²] 3. The attempt at a solution Calculating for e(1): d= 1 m F(1,2)= k[q(1)q(2)/ d²] → F(1,2)= 1.8 N F(1,2-y)= -F(1,2) sin 60º= - 1.56 N F(1,2-x)= -F(1,2) cos 60º= - 0.4 N F(1,3)= k[q(1)q(3)/ d²] → F(1,3)= 2.7 N F(1,3-y)= f(1,3) sin 60º= 2.34 N F(1,3-x)= -F(1,3) cos 60º= - 1.35 N F(1-x)= -2.25 N F(1-y)= F(1,2-y) + F(1,3-y)= 0.78 N F(1)= sqrt[F(1-x)² + F(1-y)²]= 2.39 N Are my calculations for e(1) correct? Thank you for helping!}

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# Homework Help: Calculating force on the charges placed in the corners of a triangle

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