Calculating Force Using Work-Energy Relationships

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SUMMARY

The discussion focuses on calculating the force acting on an 8 kg mass using work-energy relationships. The initial speed of the mass is 4 m/s, and after traveling 3 m, its speed increases to 5 m/s. The kinetic energy (KE) is calculated using the formula KE = 1/2 mv², and the change in kinetic energy (ΔKE) is determined to find the work done (W). The relationship W = F(Δdistance) is established, allowing for the calculation of force (F) as the work done divided by the distance traveled.

PREREQUISITES
  • Understanding of kinetic energy (KE) calculation using KE = 1/2 mv²
  • Familiarity with work-energy principles, specifically W = ΔKE
  • Knowledge of integral calculus for defining work as W = ∫ F dx
  • Concept of constant force in motion on a frictionless surface
NEXT STEPS
  • Calculate the change in kinetic energy (ΔKE) for the given mass and speeds
  • Apply the work-energy principle to derive force from work done
  • Explore the implications of constant versus variable forces in work-energy calculations
  • Study the effects of friction on work and energy in real-world scenarios
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and work-energy principles, as well as educators looking for examples of force calculations using energy concepts.

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Homework Statement


A body of mass 8 kg moves in a straight line on a horizontal frictionless surface. At one point in its path its speed is 4 m/s, and after it has traveled 3 m, its speed is 5 m/s in the same direction. Use work-energy relationships to find the force acting on the mass.


Homework Equations


PE = mgh
KE = 1/2mv2
ME = PE + KE

The Attempt at a Solution


Have no idea, do I calculate KE at first then at the second spot and get ΔKE or what? How do i get to finding the force with work-energy relationships?
 
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okay, you know that work = change in energy
so all you need to do is find what the change in energy is
you know how to calculate the kinetic energy KE=1/2mv^2, and you know the two values of v
so at worst you could be a factor of -1 off

once you have this value, which I'll call W, we can get to work trying to find the force (/bad pun)
you may or may not know (you should though) another way of defining work, that is

W=\int_{x_1}^{x_2} F dx

and we'll assume it's a constant force since nothing is mentioned about it varying, so solving this integral just becomes

W=F(x_2 - x_1)

which is force times the distance traveled, which you know
you should be able to work the force out from that

do you understand what I've just sad?
 
So Work = Force (Δdistance), where work is KE?
 

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