frogjg2003
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Make sure you're watching the signs. v<v0, and x>x0, so a should be negative. Therefore so should the force and work.
The discussion revolves around calculating the force acting on a car with a given mass and velocity, specifically in the context of braking forces and work done to stop the car over a specified distance. The subject area includes dynamics and kinematics.
The conversation is ongoing, with participants providing guidance on how to approach the problem, including the importance of free body diagrams and the equations of motion. There is an acknowledgment of confusion regarding the problem's wording and the need for clarity on initial and final velocities.
Participants note the importance of considering all forces acting on the car, including drag and braking forces, and the need to clarify the problem's assumptions. There are also reminders about the significance of units in calculations.
jamesnb said:frogjg, going back to impulse and acceleration, isn't impulse the first derivative of acceleration? Meaning if acceleration is constant, there is no impulse?
frogjg2003 said:That's not right either.
velocity is distance per time: m/s
acceleration is velocity per time: m/s/s=m/s^2
force is mass times acceleration: N=kg*m/s^2
work is force times distance: J=N*m=(kg*m/s^2)*m=kg*m^2/s^2
Keeping track of base units can sometimes be a pain, but you have to work through it.