frogjg2003
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Make sure you're watching the signs. v<v0, and x>x0, so a should be negative. Therefore so should the force and work.
The discussion focuses on calculating the force required to stop a 1320 kg car moving at 21.5 m/s in the positive x-direction over a distance of 145 m, using the equation F=MA. Participants clarify that the problem requires considering constant braking and drag forces, leading to a constant acceleration. The final calculations yield a force of -2104 N and work done of -305080 J, emphasizing the importance of unit consistency in physics calculations.
PREREQUISITESStudents in physics courses, educators teaching mechanics, and anyone interested in understanding the principles of force and motion in real-world applications.
jamesnb said:frogjg, going back to impulse and acceleration, isn't impulse the first derivative of acceleration? Meaning if acceleration is constant, there is no impulse?
frogjg2003 said:That's not right either.
velocity is distance per time: m/s
acceleration is velocity per time: m/s/s=m/s^2
force is mass times acceleration: N=kg*m/s^2
work is force times distance: J=N*m=(kg*m/s^2)*m=kg*m^2/s^2
Keeping track of base units can sometimes be a pain, but you have to work through it.