frogjg2003
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Make sure you're watching the signs. v<v0, and x>x0, so a should be negative. Therefore so should the force and work.
jamesnb said:frogjg, going back to impulse and acceleration, isn't impulse the first derivative of acceleration? Meaning if acceleration is constant, there is no impulse?
frogjg2003 said:That's not right either.
velocity is distance per time: m/s
acceleration is velocity per time: m/s/s=m/s^2
force is mass times acceleration: N=kg*m/s^2
work is force times distance: J=N*m=(kg*m/s^2)*m=kg*m^2/s^2
Keeping track of base units can sometimes be a pain, but you have to work through it.