Calculating Forces and Acceleration of a Grand Piano

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Homework Help Overview

The problem involves calculating the net force and acceleration of a 300-kg grand piano being moved by three forces with specified directions. The forces include F1 = 100 N [W20°N], F2 = 200 N [E40°S], and F3 = 300 N [S], with a coefficient of kinetic friction (μK) of 0.10.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss their calculations of the net force and question the correctness of their results, particularly regarding the direction of forces and friction. There is confusion about the interpretation of directional components and the resultant forces.

Discussion Status

The discussion is ongoing, with participants seeking clarification on their calculations and the directions of forces. Some guidance has been offered regarding the interpretation of compass directions and the role of friction in the problem.

Contextual Notes

Participants are grappling with the definitions of directions in the context of forces and friction, as well as how to correctly calculate the resultant force from the given forces.

nesan
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Homework Statement



Three movers are applying forces F1 = 100 N [W20°N], F2 = 200 N [E40°S], and F3 = 300 N on a 300-kg grand piano. If μK for the piano is 0.10, determine
a) the net force acting on the piano
b) the acceleration of the piano

The Attempt at a Solution



34rap83.png


I got an answer of 395 N going down and 276.9 going left.

Fnet = 482.38N

But the answer sheet says 106N

:(

Help please.
 
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nesan said:

Homework Statement



Three movers are applying forces F1 = 100 N [W20°N], F2 = 200 N [E40°S], and F3 = 300 N on a 300-kg grand piano. If μK for the piano is 0.10, determine
a) the net force acting on the piano
b) the acceleration of the piano

The Attempt at a Solution



34rap83.png


I got an answer of 395 N going down and 276.9 going left. (Actually is East, not left.)

Fnet = 482.38N

But the answer sheet says 106N

:(

Help please.

How in the world do you get 276.9 N going left?
 
SammyS said:
How in the world do you get 276.9 N going left?

I subtracted the amount of force going right from the friction. Is that wrong?
 
nesan said:
I subtracted the amount of force going right from the friction. Is that wrong?

In which direction does the friction force act?
 
nesan said:
I subtracted the amount of force going right from the friction. Is that wrong?
That's wrong.

These are compass directions.

The positive y direction is North, not up, etc.

Gravity acts in the direction into the page. The normal force is out of the page.


Find the resultant force for the three given forces. Assuming that the direction of motion is in the direction of the acceleration, you can then account for the direction in which the friction force acts.
 

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