Calculating Forces and Magnitude for a 2.50 kg Block on a Frictionless Table

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SUMMARY

The discussion focuses on calculating the forces acting on a 2.50 kg block pushed by a 17.0 N force at an angle of 22.6° below the horizontal on a frictionless table. The normal force exerted by the table is determined to be 24.50 N, balancing the gravitational force and the vertical component of the applied force. The net force on the block is calculated by resolving the applied force into its horizontal and vertical components, confirming that there is no movement in the y-direction. A free body diagram (FBD) is essential for visualizing the forces acting on the block.

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  • Understanding of Newton's laws of motion
  • Knowledge of free body diagrams (FBD)
  • Ability to resolve forces into components
  • Familiarity with basic trigonometry, specifically sine and cosine functions
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  • Study the resolution of forces into components using trigonometric functions
  • Explore Newton's second law of motion in detail
  • Investigate the concept of net force and its implications in motion
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Students in physics, educators teaching mechanics, and anyone interested in understanding force calculations in a frictionless environment.

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A block of mass 2.50 kg is pushed 2.18 m along a frictionless horizontal table by a constant 17.0 N force directed 22.6o below the horizontal.

Determine the magnitude of the normal force exerted by the table.
and
Determine the net force on the block.

I already found that the work done by the applied force is 3.42×101 J and the magnitude of the force of gravity is 24.50 N. I just don't know what to do to find the other two, I have tried several different equations but none of them are seeming to work for me...
 
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Have you set up a FBD? If you do, you'll see that there's three forces that at least partly act in the y-direction. There's no movement in the y-direction, which tells you what about the forces?
 
You need to resolve the Force applied into normal and parallel to the surface components.

That's where the 22.6° angle comes in.
 

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