Two blocks on a frictionless surface; find the force

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Homework Help Overview

The problem involves two blocks, A and B, being pushed on a frictionless surface by a force of 30 N. The objective is to determine the force that block B exerts on block A, given their respective masses of 2.0 kg and 4.0 kg.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the total force acting on the blocks and attempt to break down the forces acting on each block individually. There are questions about expressing the solution using Newton's second law and clarifying the relationship between the forces acting on the blocks.

Discussion Status

Some participants have provided guidance on applying Newton's second law to the problem, while others seek clarification on how to formalize their reasoning. There is an ongoing exploration of the forces involved and their interactions.

Contextual Notes

Participants are navigating the application of Newton's laws and the implications of action-reaction pairs in the context of the problem setup.

Peter Halsall
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Homework Statement


Two blocks, A and B , are being pushed on a frictionless surface by a froce of 30 N to the right, .Block A has a mass of 2.0kg, Block B, being pushed by Block A is 4.0kg. Calculate the magnitude of the force that block B exerts on Block A.

Homework Equations


f=ma

The Attempt at a Solution


If The total force pushing the blocks as a system is 30 N, then if you treat the objects as individuals 20 N of the force is provided by Block B and 10 N by Block A. So 20 N is the magnitude of the force that Block B exerts on Block A
 
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Is fine, but can you express it more formally in terms of ##F = ma## for the ensemble and for each of the blocks ?
 
BvU said:
Is fine, but can you express it more formally in terms of ##F = ma## for the ensemble and for each of the blocks ?
I'm sorry, I don't understand what your asking, do you want me to prove it using Newton's 2nd law?
 
Yes. F = ma for the total, a is the same for A and B so with F = ma for B the force needed to accelerate B is the 20 N you found. And from Newton 3 B exerts a reaction force of the same magnitude on A.
 

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