Calculating Forces and Potential Energy Changes: Integrals, Curl, and Work

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SUMMARY

The discussion focuses on calculating forces and potential energy changes using integrals, curl, and work. The potential energy function given is U(x,y) = 3x² - 7y. The force at the point (3,3) is calculated as F(3,3) = -18i + 7j, with a magnitude of 19.31 N, although the expected answer is 21.2 N. The discussion also covers determining the conservativeness of forces through curl calculations and finding work done by a force F = 6i - 2j on a particle with displacement S = 3i + 5j, yielding W = 8 N and an angle of 77.5 degrees between the two vectors.

PREREQUISITES
  • Understanding of vector calculus, specifically partial derivatives
  • Familiarity with the concepts of conservative forces and curl
  • Knowledge of calculating work done by a force
  • Basic proficiency in trigonometry for angle calculations
NEXT STEPS
  • Study the properties of conservative forces and their relationship with potential energy
  • Learn about curl in vector fields and its implications for force fields
  • Explore the concept of work done by varying forces in different coordinate systems
  • Investigate the application of integrals in calculating potential energy changes
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Students in physics or engineering, particularly those studying mechanics, vector calculus, and energy conservation principles.

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Homework Statement



U(x,y) = 3x2 - 7y

A) Calculate the force at the coordinate point (3,3)

B) Determine if the following forces are conservative and find the change in potential energy correspoinding to each for an interval 0 to x

i) Fx = ax + bs2 a and b are constants

ii) Fx = AeBx (A and B are constants)

c) a force F = 6i - 2j acts on a particle that undergoes a displacement of S = 3i + 5j

i)find the work done by the force on the particle
ii) find the angle between F and S

Homework Equations





The Attempt at a Solution



Part A)

by book says F(x,y) = -dU/dx i - dU/dy j those are partial derivatives

so F = -6xi + 7j

then F(3,3) = -18i + 7j and the magnitude is 19.31 N, the answer is given as 21.2 what's my mistake

Part B)

it says you need to take the curl and if it is 0, then it is conservative

i) curl F = (-a - 2bx)j + (a + 2bx)k = 0

ii) curl F = -ABeBx i + ABeBx k = 0

Part C)

i) W = F dot S = 18 - 10 = 8 N

ii)thetaF = arctan -2/6 = -18.4 degress
thetaS = artcan 5/3 = 59.0 degrees

59.0-18.4 = 77.5 degrees
 
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For part A

when taking the partial derivative w.r.t.x you hold y as a constant

so U= 3x2 - 7y
∂U/∂x= ∂/∂x(3x2 - 7y), so -7y is essentially treated like a constant.
 
i did that dU/dx = 6x DU/dy = -7
 

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