Calculating Forces on Steel Barbell & Trash Compactor - Pressure Questions

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SUMMARY

The discussion focuses on calculating the forces exerted on a 35-kg steel barbell when lifted underwater and the force applied in a hydraulic press used in a trash compactor. The buoyant force acting on the barbell is determined using Archimedes' principle, which states that the buoyant force equals the weight of the displaced fluid. The user also discusses the dimensions of the hydraulic press, with an input piston radius of 6.1 x 10-3 m and an output plunger radius of 4.5 x 10-2 m, and an input force of 300 N, leading to the calculation of the output force applied to the trash.

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A bodybuilder is holding a 35-kg steel barbell above her head. How much force would she have to exert if the barbell were lifted underwater?

In the hydraulic press used in a trash compactor, the radii of the input piston and the output plunger are 6.1 10-3 m and 4.5 10-2, respectively. If the height difference between the input piston and the output plunger can be neglected, what force is applied to the trash when the input force is 300 N?

Please answer these questions for me, they are the last two problems on my 100 problem worksheet that is due tomorrow. I have literally spent the past two hours trying to find the answers for these and i really need a good grade...Thanks in advance!
 
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My problem for the first one is that i can't find any formulas or theories in my textbook that explain the situation. I answered the second problem what i think is correctly so please ignore that part.
 
ok archimedes' principle states that the magnitude of buoyant force=weight of displaced fluid. But How can i have any idea what the weight of the displaced fluid is?
 
I also know that the mass density of steel is 7860 kg/m^3, while the mass density of water is 1000 kg/m^3
 
nevermind i solved it
 

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