Calculating Frequency of Star's Radio Signals from Earth

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SUMMARY

The calculation of the frequency of radio signals received from a star moving at 0.8c away from Earth results in a reception rate of 0.45 signals per second. This is derived using the time dilation formula Δts = Δtm/√(1 – (v^2/c^2)), where Δtm is the time interval of 1 second according to the star's time scale. The solution confirms that the signals are received less frequently due to the relativistic effects of the star's velocity, specifically time dilation. Additionally, the increasing distance of the signals must be considered for a complete analysis.

PREREQUISITES
  • Understanding of special relativity concepts, particularly time dilation.
  • Familiarity with the formula Δts = Δtm/√(1 – (v^2/c^2)).
  • Basic knowledge of frequency calculations in physics.
  • Awareness of the implications of relativistic motion on signal transmission.
NEXT STEPS
  • Study the implications of relativistic Doppler effect on signal frequency.
  • Learn about the effects of increasing distance on signal reception.
  • Explore advanced topics in special relativity, including Lorentz transformations.
  • Investigate practical applications of time dilation in astrophysics and communication technologies.
USEFUL FOR

Students and enthusiasts in physics, particularly those studying special relativity, as well as professionals in astrophysics and telecommunications who are interested in the effects of relativistic motion on signal transmission.

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Homework Statement



A distant star has been measured as moving at a speed of 0.8c away from Earth. If a planet of this star sends radio signals to Earth once every second (according to their time scale), how often would we receive them (according to out time scale)?

Homework Equations



Δts = Δtm/ √(1 – (v^2/c^2)

The Attempt at a Solution



Δts = Δtm/ √(1 – (0.8c)^2/c^2)
= 1/ √(1 – (0.8c)^2/c^2)
= 2.24 s

f = 1/2.24 s
= .45 signal/second

Therefore, we would receive .45 signal/second

*does this look ok?
 
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hi crosbykins! :smile:

have you taken account of the fact that the distance each signal has to travel is increasing?
 

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