Calculating frictional force for a rolling wheel | F=ma and t=I(a/r) equations

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SUMMARY

The discussion focuses on calculating the frictional force acting on a rolling wheel subjected to a constant horizontal force of 17 N. The wheel has a mass of 6 kg and a radius of 0.70 m, with an acceleration of 1.00 m/s². Participants clarify that the moment of inertia (I) for the wheel should be treated as I = mr², as it is considered a hoop. The equations F = ma and τ = I(a/r) are utilized to derive the frictional force.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Knowledge of rotational dynamics, specifically torque (τ = I(a/r))
  • Familiarity with moment of inertia for different shapes, particularly hoops and discs
  • Basic algebra for solving equations with multiple variables
NEXT STEPS
  • Study the derivation of the moment of inertia for various geometric shapes, including hoops and solid discs
  • Learn how to apply Newton's laws in rotational motion scenarios
  • Explore the relationship between linear and angular acceleration in rolling objects
  • Investigate real-world applications of frictional forces in rolling motion
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Physics students, mechanical engineers, and anyone interested in the principles of dynamics and rotational motion.

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In the figure below, a constant horizontal force Fapp of magnitude 17 N is applied to a wheel of mass 6 kg and radius 0.70 m. The wheel rolls smoothly on the horizontal surface, and the acceleration of its center of mass has magnitude 1.00 m/s2.

(a) In unit-vector notation, what is the frictional force on the wheel?




F=ma , t=I(a/r)



The Attempt at a Solution


- I set up both equations with my applied force and frictional force, so I have 2 unknows in my I and frictional force. My problem is coming in not knowing what to sub in for I. I don't know whether a wheel would be considered a solid disc or a hoop. My initial thinking would be I=mr^2, and then I could plug that in into the torque equation and cancel out my r and then solve for frictional force. Would that be correct?
 
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A wheel would be a hoop... hence I = mr^2.
 

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