Calculating Frictional Force of a Sliding Mass

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Homework Help Overview

The problem involves calculating the frictional force acting on a 10.0-kg mass sliding down a 25.0-degree incline, with given coefficients of static and sliding friction. The original poster seeks clarification on the calculation of the frictional force while the mass is in motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of the frictional force using the coefficient of sliding friction and the mass's weight components. There is mention of the need to find the force acting down the ramp and the net force along the ramp.

Discussion Status

Some participants confirm the original poster's calculation of the frictional force and suggest additional steps to analyze the forces acting on the mass. There is an emphasis on drawing a free-body diagram to visualize the forces involved.

Contextual Notes

The original poster expresses a need for a detailed explanation of the steps involved in solving the problem, indicating a desire for deeper understanding rather than just the final answer.

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Homework Statement



A 10.0-kg mass is placed on a 25.0o degree incline and friction keeps it from sliding. The
coefficient of static friction in this case is 0.580, and the coefficient of sliding friction is
0.520. The mass is given a shove causing it to slide down the incline.

Homework Equations



What is the frictional
force while the mass is sliding?

The Attempt at a Solution



This is all I have so far, but I don't exactly understand it:

Frictional force while the mass is sliding = μmgcosθ = 0.52 X 10 X 9.8 X cos 25
= 46.19 N


I need a full step-by-step explanation, if possible. I'll also take any other information about the problem that may make it easier. Thank you.
 
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Your 46.19 is correct.
You also need to find the downward, along the ramp force. It is the other component of mg, that is mg*sin(25). The net force along the ramp is this force minus the friction force.

I always draw the ramp, put the mass at the very top and draw the mg force vector straight down. Then separate that mg into the sum of a force along the ramp and perpendicular to the ramp. The perpendicular force is the normal force pulling the mass against the ramp surface.
 


Welcome to PF;
Draw a free-body diagram for the mass and you'll see how that relation was found.
 


Delphi51 said:
Your 46.19 is correct.
You also need to find the downward, along the ramp force. It is the other component of mg, that is mg*sin(25). The net force along the ramp is this force minus the friction force.

I always draw the ramp, put the mass at the very top and draw the mg force vector straight down. Then separate that mg into the sum of a force along the ramp and perpendicular to the ramp. The perpendicular force is the normal force pulling the mass against the ramp surface.

Simon Bridge said:
Welcome to PF;
Draw a free-body diagram for the mass and you'll see how that relation was found.

I'll do all of the above. Thank you.
 


Cool! Let us know how you get on.
 

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