Calculating ga on Earth and an Asteroid using F=-kx Formula

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SUMMARY

The discussion focuses on calculating gravitational acceleration (ga) on Earth and an asteroid using the formula F = -kx. The user has a 2 kg mass and a spring balance, with known values of gravitational acceleration on Earth (g = 9.81 m/s²) and spring extension measurements of 100 mm on Earth and 110 mm on the asteroid. The user seeks clarification on whether to apply the formula F = -kx for both scenarios and equate it to F = mg to find ga on the asteroid.

PREREQUISITES
  • Understanding of Hooke's Law (F = -kx)
  • Basic knowledge of gravitational force (F = mg)
  • Familiarity with units of measurement (meters, kilograms, seconds)
  • Ability to perform calculations involving spring constants and gravitational acceleration
NEXT STEPS
  • Calculate the spring constant (k) using the extension data from Earth.
  • Apply the calculated spring constant to determine ga on the asteroid.
  • Explore the implications of varying gravitational forces on different celestial bodies.
  • Review concepts related to gravitational fields and their measurements in physics.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and gravitational forces, as well as educators looking for practical examples of gravitational calculations.

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Homework Statement



You have to do a measurement of ga using a different method. You have in your equipment a standard 2 kg mass and an accurate spring balance. You know that on Earth, at a place with g = 9.81 m s−2, that a mass of 20g produced an extension of 100 mm. On the asteroid surface, you suspend your standard kilogram mass from the spring and measure an extension of
110 mm.

Calculate ga.

Homework Equations



F=-kx

The Attempt at a Solution



do i use this forumal F=-kx twice,
first when his on the Earth then when on asteroid.
and then eqating this value to f=mg

[need help]
 
Physics news on Phys.org
Well if you found ga in another part of the question already, why don't you just try your method and see if you get the same answer?!
 

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