Calculating Generator Shaft Torque

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SUMMARY

This discussion centers on calculating the torque of a generator shaft for a Permanent Magnet Generator (PMG) producing 5 kW at 840 V and 189 RPM. The manufacturer claims a shaft torque of 350 Nm at full power extraction, which is inconsistent with the calculated torque of 252.6 Nm using the formula Torque = Power x 60 / (2 x PI x Rot). Participants question the relationship between motor torque and generator torque, exploring the feasibility of driving the 5 kW generator with a 2.2 kW motor at 3600 RPM through an 18:1 gear reduction.

PREREQUISITES
  • Understanding of torque calculations in electrical engineering
  • Familiarity with Permanent Magnet Generators (PMG)
  • Knowledge of gear reduction principles
  • Basic grasp of power equations in rotational systems
NEXT STEPS
  • Research the formula for calculating torque in generators and motors
  • Learn about gear reduction ratios and their impact on torque output
  • Investigate the efficiency losses in power transmission systems
  • Explore the relationship between motor and generator torque in detail
USEFUL FOR

Electrical engineers, automation integrators, and anyone involved in the design and optimization of generator systems will benefit from this discussion.

donbcg
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Gentlemen,

Here is my scenario. I am building a new project utilizing a PMG that produces 5KW at 840V at 189 RPM. The manufacturer is supplying me with a torque curve that does not appear to be correct. They say, at full power extraction it has 350Nm of shaft torque. Is this correct? If so, why? That equates to roughly 20HP or 18KW.

This is either a wasteful course to generate electricity, or the math is being lost in translation.

I am in the PLC/Autmation Integrator arena and haven't the correct formula to calculate. Nor do I now what information is required to build the equation. Motor torque, easy. Generator torque, not so much.

I appreciate all the assistance in advance.

Don
 
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5kW@189RPM = 252.6N.m

350N.m@189RPM = 6.93kW

Using Power [W] and Rot [RPM] to get Torque [N.m], the equation will be:

Torque = Power x 60 / (2 x PI x Rot)
 
john.phillip said:
5kW@189RPM = 252.6N.m

350N.m@189RPM = 6.93kW

Using Power [W] and Rot [RPM] to get Torque [N.m], the equation will be:

Torque = Power x 60 / (2 x PI x Rot)

Is it true then that there is a direct corelation between motor torque and generator torque? Why is this the same? Shouldn't it take less torque to make rather than use?

Let's say I drive the 5K @189RPM generator with a 2.2K@3600 motor geared appr. 18:1. Is it possible to do this?
 
Apply the equation to 2.2kW@3600 to get the input torque.

Using the 18:1 reduction, the output torque will be greatly increased. Will this increased output torque supply the required torque of 252.6N.m for the generator ?

If not, what would be the generated power, disregarding transmission efficiency losses ?
 

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