Calculating Heat Absorption in an Automobile Cooling System with 18L of Water

[needhelp83]

An automobile cooling system holds 18 L of water. How much heat does it absorb if its temperature rises from 20oC to 90oC?

V= 18 L=0.018 m3
m=pV=(1.0*103 kg/ m3 )(0.018 m3 )= 18 kg

Q=mcT=(18 kg)(4186 J/kg*Co)( 90o-20o)= 5,274,360 J

The answer in the book says it should be 4.7*10^6, but I don't know how they derived to that answer. Any help

 

[needhelp83]

Any help from anybody?

 

[QuantumCrash]

Are you sure that is all the information given? Your calculations seems right to me.

 

[needhelp83]

Yes that was all that was given...I thought I was correct also, maybe the book made a mistake...it has been known to happen. Thanks for the help!