Calculating Heat of Reaction at 1200K: TiCl4 + O2 → TiO2 + 2Cl2

  • Thread starter Thread starter sero2000
  • Start date Start date
  • Tags Tags
    Heat Reaction
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
2 replies · 2K views
sero2000
Messages
27
Reaction score
0

Homework Statement


I am given the following chemical eqn

TiCl4(g) + O2 → TiO2 (s) + 2Cl2

I am also given some values on the heat of formation and the entropy of the substances but however only at 300Kelvin and i am given some values and the formula to calculate Cp of the substances

The question asks about the heat of reaction when the process is at 1200Kelvin.

Im just not too sure how to start. Am i able to just take the heat of formation values at 300K? IF i were to find out the heat of reaction for this process at 300k, is it possible that i integrate the Cp equation with T2 = 1200K and T1=300k?
 
Last edited:
Physics news on Phys.org
sero2000 said:

Homework Statement


I am given the following chemical eqn

TiCl4(g) + O2 → TiO2 (s) + 2Cl2

I am also given some values on the heat of formation and the entropy of the substances but however only at 300Kelvin and i am given some values and the formula to calculate Cp of the substances

The question asks about the heat of reaction when the process is at 1200Kelvin.

Im just not too sure how to start. Am i able to just take the heat of formation values at 300K? IF i were to find out the heat of reaction for this process at 300k, is it possible that i integrate the Cp equation with T2 = 1200K and T1=300k?
Yes. You have the right idea. First, you take the change in enthalpy to bring the reactants down to 300 K, then you take the heat of reaction at 300 K, then you take the change in enthalpy to bring the products back up to 1200 K. This is the same as the heat of reaction at 1200 K. You integrate the heat capacities to get heat effects involved in cooling the reactants and heating the products.

Chet