Calculating heat recovery from engine exhaust gases

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SUMMARY

This discussion focuses on calculating heat recovery from the exhaust gases of a Jenbacher J620 gas-fueled engine. The user reports an exhaust gas mass flow of 17325 kg/hr and an exhaust temperature of 425°C, leading to a claimed recoverable thermal output of 3020 kW. However, using the formula Qdot = mdot X Cp X delta T, the user calculates only 1688 kW, indicating a discrepancy. The conversation suggests that the manufacturer may include additional factors such as mechanical work from the turbo and heat recovery from other engine components in their efficiency claims.

PREREQUISITES
  • Understanding of thermodynamics, specifically heat transfer principles.
  • Familiarity with the Jenbacher J620 engine specifications.
  • Knowledge of specific heat capacity (Cp) calculations for combustion gases.
  • Experience with combined heat and power (CHP) systems and their efficiencies.
NEXT STEPS
  • Research the specific heat capacity of combustion gases at varying temperatures.
  • Investigate the operational parameters and efficiency metrics of the Jenbacher J620 engine.
  • Learn about the mechanical work done by exhaust gases in turbocharged engines.
  • Explore methods for calculating total heat recovery in CHP systems, including auxiliary heat sources.
USEFUL FOR

Engineers, energy analysts, and students involved in thermodynamics, waste heat recovery, and CHP system design will benefit from this discussion.

LT Judd
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TL;DR
I am having trouble calculating the recoverable energy from a gas engine exhaust gas stream . Jenbacher J620 3000kw engine.My figures don't match the makers claims.
Hello,
I am doing a study for my final years Uni project, which includes waste heat recovery from gas fuelled engine exhaust. I am using a data sheet for a Jenbacher J620 engine-.
In the data sheet it is stated that;
exhaust gas mass flow (wet) = 17325 kg hr ( not sure about the wet part?) this becomes 4.81 kg/s
exhaust gas temperature = 425 degC
recoverable thermal output (120 °C) = 3020 kw - I assume that means when exhaust gs is reduced to 120 deg C.

This gives an overall efficiency of 86% (thermal Plus electrical)

However when I apply the formula Qdot = mdot X CpX delta T
I get 4.81 X 1.15 X 305, which only comes to 1688 Kw , about half the claimed value !??
The claimed value doesn’t seem unreasonable because a review of the literature seems to show overall CHP efficiencies of 70-80% are the norm.

I did a mass weighting of different products of combustion of methane and 70% excess air to come up with that Cp,- a bit of a fudge, but its not that much difference to the Cp of straight air at 650K. The Cp would have to be about twice that to match the makers claimed figures for heat recovery.
I must be missing something- but what ??
Gas engine paramaters.JPG
??
 
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LT Judd said:
...
I must be missing something- but what ??
I would recommend consulting the manufacturer of the engine.
Perhaps they are computing the mechanical work done by the gasses on the turbo.
There is minimum limit to the temperature of the gases, below which sulfuric acid begins to damage the exhaust system and surroundings of the engine.
 
Probably including all heat recovered from jacket cooling water , lube oil cooler and turbocharger intercooler, in the figure.
 

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