Calculating Impulse and Work on a Bullet

Click For Summary
SUMMARY

The discussion focuses on calculating the impulse and work done on a bullet with a mass of 0.010 kg and an initial speed of 100 m/s, which comes to rest after penetrating a wooden block by 0.10 m in 0.02 seconds. The impulse delivered to the bullet is determined using the formula Ft = Δ(mv), where F is force, t is time, Δ is change, m is mass, and v is velocity. The participants clarify that impulse is measured in Newton-seconds (Ns) or kg·m/s, and emphasize that the change in mass is not required for this calculation since the bullet's momentum changes without altering its mass.

PREREQUISITES
  • Understanding of impulse and momentum concepts
  • Familiarity with the formula Ft = Δ(mv)
  • Basic knowledge of kinematics and dynamics
  • Ability to perform calculations involving mass, velocity, and time
NEXT STEPS
  • Study the relationship between impulse and momentum in physics
  • Learn how to calculate work done using the work-energy principle
  • Explore the concept of force and its relation to motion
  • Investigate real-world applications of impulse in collision scenarios
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of impulse and work calculations in projectile motion.

Spaniard
Messages
10
Reaction score
0

Homework Statement


A bullet of mass 0.010 kg and speed of 100 m/s is brought to rest in a wooden block after penetrating a distance of 0.10 m. This process takes 0.02 seconds. Theblock remains stationary during this process.

a. what is the magnitude of the impulse delivered to the bullet by the block during this time?

b. How much work was done ont he bullet during this process?


Homework Equations


thats what I am wondering


The Attempt at a Solution


i can't find the formula to try it, i am pretty much just looking for the formula and what each thing stand for etc. Thanks
 
Physics news on Phys.org
Try using Ft=Δ(mv)
 
sorry sounds dumb but what does F,t, delta, and mv stand for?
 
no that's a perfectly decent question! if you have never come across this equation you can't be expected to know what it means!
F= force
t= time
delta= change in
m= mass
v= velocity
just a note, the product Ft is known as impulse =]
 
ok so i have the change in velocity, and time, but the problem says nothing about the change of mass. and don't have the force so I am assuming there's a separate formula involving how much the bullet penetrated that will give me the force or change of mass but I am thinking force. Anyone know what formula i hsould use or where i go from here? thanks
 
note that Ft=Δ(mv)
mv is just the bullet's momentum, for the momentum to change you don't necessarily have to change the mass
 
whats the unit measure for impulse? Btw it all makes sense now. Thanks
 
Ns or kgms^-1
what was the answer then?? just to check if i got it right as well =]
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
7K
  • · Replies 28 ·
Replies
28
Views
9K
  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
14
Views
4K
Replies
25
Views
3K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K