Calculating Impulse for a Leaping Cricket: A Physics Problem

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Homework Statement


A 20 g cricket (Acheta domestica) leaps through a 2.2 m horizontal distance. The initial velocity of the cricket makes a 28° angle with the horizontal direction. If it takes the cricket 0.010 s to leave the ground, what is the magnitude of the impulse of the total force on the cricket that gives it the speed needed for the jump?


Homework Equations


I = F[tex]\Delta[/tex]t = [tex]\Delta[/tex]p
Motion formulas


The Attempt at a Solution


Did not know how to approach problem

THanks
 
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First solve the projectile motion problem: How fast must the cricket leap at the given angle to reach 2.2m?

Then you can worry about the needed impulse.
 
Thanks I got it now.