Calculating Impulse for a Leaping Cricket: A Physics Problem

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To calculate the impulse for a leaping cricket, first determine the required initial velocity to cover a horizontal distance of 2.2 m at a 28° angle. Using projectile motion equations, the necessary speed can be calculated. Once the speed is known, apply the impulse-momentum theorem, where impulse equals the change in momentum over the time of the jump (0.010 s). The discussion emphasizes solving the projectile motion aspect before addressing the impulse calculation. This structured approach ensures accurate results for the cricket's leap.
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Homework Statement


A 20 g cricket (Acheta domestica) leaps through a 2.2 m horizontal distance. The initial velocity of the cricket makes a 28° angle with the horizontal direction. If it takes the cricket 0.010 s to leave the ground, what is the magnitude of the impulse of the total force on the cricket that gives it the speed needed for the jump?


Homework Equations


I = F\Deltat = \Deltap
Motion formulas


The Attempt at a Solution


Did not know how to approach problem

THanks
 
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First solve the projectile motion problem: How fast must the cricket leap at the given angle to reach 2.2m?

Then you can worry about the needed impulse.
 
Thanks I got it now.
 
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