Calculating Induced EMF in a Moving Loop of Wire with Uniform Magnetic Field

  • Thread starter Thread starter mmm62892
  • Start date Start date
  • Tags Tags
    Emf
Click For Summary
SUMMARY

The discussion focuses on calculating the induced electromotive force (emf) in a square loop of wire measuring 2.00 cm per side, moving at a speed of 15.0 m/s into a uniform magnetic field of 56.0 T. Using Faraday's Law, the induced emf can be determined after the loop has traveled 1.00 cm into the field. The resistance of the loop is given as 1.60 Ω, allowing for the calculation of the current flowing through the loop once the emf is established. The direction of the current can be determined using the right-hand rule.

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Familiarity with the concept of magnetic flux
  • Basic knowledge of Ohm's Law
  • Ability to apply the right-hand rule for current direction
NEXT STEPS
  • Study the principles of Faraday's Law in detail
  • Learn how to calculate magnetic flux through a loop of wire
  • Explore the right-hand rule for determining current direction in electromagnetic contexts
  • Investigate the relationship between velocity and induced emf in moving conductors
USEFUL FOR

Physics students, electrical engineers, and educators looking to deepen their understanding of electromagnetic induction and its applications in real-world scenarios.

mmm62892
Messages
1
Reaction score
0
Picture link: http://es.tinypic.com/r/5cx154/5
A square loop of wire measures 2.00 cm on each side. It is attached to a cart that is moving at a constant speed of 15.0 m/s into a uniform magnetic field of 56.0 T. (a) What is the induced emf after it has traveled 1.00 cm into the field? (b) What is the direction of the current, clockwise or counterclockwise? (c) If the resistance of the loop is 1.60 , what is the current in the loop?

What is this even asking and how does a cart have to do with emf? I'm so lost. :(
 
Physics news on Phys.org
Have you learned about Faraday's Law? That would be the place to start. How is the velocity of the cart related to the change of the magnetic flux through the wire loop?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
Replies
4
Views
1K
Replies
4
Views
906
Replies
1
Views
1K
Replies
2
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
11
Views
3K
Replies
1
Views
2K
Replies
8
Views
2K