Calculating Initial Concentrations for Clock Reaction Lab | Trial Data Included

  • Thread starter Thread starter ashley_s_411
  • Start date Start date
  • Tags Tags
    Lab Reaction
Click For Summary
SUMMARY

The discussion focuses on calculating the initial concentrations of potassium iodate (KIO3) in a clock reaction lab experiment involving sodium bisulfite (NaHSO3). The formula C1V1=C2V2 is utilized to determine concentrations, with KIO3 at 0.0200 mol/L and NaHSO3 at 0.00200 mol/L. The user successfully calculates the concentration for Trial 1 but seeks clarification on how to adjust calculations for subsequent trials where water is added. The correct approach involves adjusting the total volume in the formula to account for the added water.

PREREQUISITES
  • Understanding of molarity and concentration calculations
  • Familiarity with the formula C1V1=C2V2
  • Basic knowledge of chemical reactions and solutions
  • Ability to perform unit conversions and volume adjustments
NEXT STEPS
  • Learn how to apply the dilution formula C1V1=C2V2 in various scenarios
  • Study the effects of volume changes on concentration calculations
  • Explore the principles of clock reactions in chemistry
  • Investigate the role of sodium bisulfite in redox reactions
USEFUL FOR

Chemistry students, lab technicians, and educators involved in experimental design and concentration calculations in chemical reactions.

ashley_s_411
Messages
1
Reaction score
0
Reaction Lab (NEED HELP!)

1. This is a clock reaction lab where you have 10mL of KIO3 solution in a beaker, and you are adding 10mL of NaHSO3 solution to it. You then start the stopwatch and wait until the solution turns blue. I need to calculate the initial concentrations of KIO3 in each of the mixtures for part A after mixing. There are trials in total, and I will show my data as well. There is always 10mL of NaHSO3 in the beaker.
Trial 1: Add 10mL KIO3
Trial 2: Add 7mL KIO3 and 3mL Water
Trial 3: Add 5mL KIO3 and 5mL Water
Trial 4: Add 3mL KIO3 and 7 mL Water

My Teacher says to use the formula C1V1=C2V2, but I don't know which values to put where.

*Note: Concentration of KIO3= 0.0200 mol/L
Concentration of NaHSO3= 0.00200 mol/L 3. My Attempts:

I have tried for Trial one and this is what I got:
C1=what I am solving for
V1=10.00 mL
C2=0.00200 mol/L
V2=20.00 mL

c1=c2v2/v1
=0.00200 mol/L x 20.00 mL/10.00mL
=0.004 mol/L

Is this right? I just don't get what to do for the next 3 trials because water is added?

Thanks so much!

Homework Statement


Homework Equations


The Attempt at a Solution

 
Physics news on Phys.org


You could us the variables subscripted as 1 for initial C and V, and subscripted 2 for final C and V.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
13K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
10K
Replies
8
Views
6K
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
13K
  • · Replies 4 ·
Replies
4
Views
39K
Replies
8
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K