Calculating Initial Velocity to Make a 10m Basketball Shot

[utsharpie]

a basketball player is 1.9m tall, wants to make a basket 10m away. the basket is 3.05m tall. gravity is 9.8, if he shoots from a height of 1.91m at 33.3 degree angle, what initial speed is thrown to make a basket?

i have no clue how to find initial velocity when it isn't given.

 

[Hootenanny]

You have both a horizontal and vertical distance, with a vertical acceleration. The velocity will have two perpendicular components (horizontal and vertical). You know how far horizontally and vertically it must travel to reach the basket therefore you should be able to work out the flight time (using simulataneous equations and equations of motion) and then calculate the velocity and resolve the components. Start working through it and I'll try to help you along the way.

 

[utsharpie]

ok i think Vy is 4.726

 

[Hootenanny]

can you show your working? Also where is the angle taken from (horizontal or vertical)

 

[utsharpie]

the angle is on the horizontal. nevermind on that Vy answer. I am stumped. how do i find Vxo and Vyo? is Y just the difference in the goal height and the height from which he shot? so Y is 1.14? and x is 10m?

 

[utsharpie]

the angle is on the horizontal. i think i need to use formula V2y=V2oy-2gdeltay? nevermind on my answer about Vy...Im stumped

edit..

ok Vfy2=0+2(9.8)(1.14)
Vfy=4.726 m/s