Calculating Initial Volume for Desired Pressure and Volume in Air Chamber

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SUMMARY

The discussion focuses on calculating the initial volume required for an air chamber to maintain a pressure of 9 ± 1 bar (131 ± 15 psi) while allowing 25 ± 2.5 mL of air to flow out. The user estimates that starting at 10 bar and reducing to 8 bar after the volume loss leads to the equation 10v – 8v = 250. The calculated initial volume required is 125 mL to achieve the desired pressure and volume conditions.

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  • Understanding of gas laws, particularly Boyle's Law
  • Basic knowledge of pressure measurement in bars and psi
  • Familiarity with volume calculations in milliliters
  • Experience with ratiometric problem-solving techniques
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pyzaan
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Hi,

I am wondering if anyone can help me out with this, I'm looking to create 9 ± 1 bar (131 ± 15 psi) of Entry Water pressure for 15-25 seconds to create a 25 ± 2.5 mL of volume as it pass through 7 ± 0.5 g (0.25 ± 0.02 oz) of finelyy ground material. If I were to pressurize an air chamber what size/volume would be required to achieve the above?
 
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Needs to maintain pressure = 9 ± 1 bar, while 25 ml of (compressed) air flows out.
Start at 10 bar, following 25ml loss reduced to 8 bar. The problem is ratiometric.

As an estimate; solve for the initial volume required, v;
10 / 8 = v / (v – 25)
10v – 8v = 250
Therefor initial volume v = 125 ml.
 

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